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harina [27]
3 years ago
15

Solve the question above please​

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

5x5

Step-by-step explanation:

What I did was that I worked out how x is 2 and then x equals 5

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2 x 10 + 4 x 1 + (7 x 1/10) + (4 x 1/100) + (5 x 1/1000) in standard form
Verizon [17]

Answer:

4949/200=

Step-by-step explanation:

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3 years ago
Harry and John share £60 in the ratio of 2: 1 work out how much money Harry gets ​
krek1111 [17]

Answer:

40

Step-by-step explanation:

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3 years ago
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

4 0
3 years ago
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