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kykrilka [37]
3 years ago
12

WILL GIVE 100 POINTS TO WHOEVER ANSWER THIS CORRECTLY. In the similarity transformation of abc to def, abc was dilated by a scal

e factor of ?, reflected across the , and moved through the translation

Mathematics
1 answer:
Contact [7]3 years ago
5 0

Answer:

Dialated by a scale factor of two, reflected across the x axis, and transformed three units left

Step-by-step explanation:

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X^2 + 6^2 = 7^2 what’s the value of X?
CaHeK987 [17]

Step-by-step explanation:

,3^2+5^2=x^2

(3+5)^2=x^2

(8)^2=x^2

64=x^2

x=√64

X=8

8 0
3 years ago
Which of the following summary measures for forecast errors does not depend on the units of the forecast variable? a. MFE (mean
Orlov [11]

Answer:

d. The mean absolute percentage error (MAPE) does not depend on the units of the forecast variable.

Step-by-step explanation:

A forecast error is the difference between the actual or real and the predicted or forecast value of a time series or any other phenomenon of interest. Here “error” does not mean a mistake, it means the unpredictable part of an observation.

There are many different ways to summarize forecast errors in order to provide meaningful information.

Scale-dependent errors. The forecast errors are on the same scale as the data. The two most commonly used scale-dependent measures are based on the absolute errors or squared errors:

\begin{align*}  \text{Mean absolute error: MAE} & = \text{mean}(|e_{t}|),\\  \text{Root mean squared error: RMSE} & = \sqrt{\text{mean}(e_{t}^2)}.\end{align*}\text{Mean absolute error: MAE} & = \text{mean}(|e_{t}|),\\  \\\text{Root mean squared error: RMSE} & = \sqrt{\text{mean}(e_{t}^2)}.

Percentage errors. Percentage errors have the advantage of being unit-free, and so are frequently used to compare forecast performances between data sets. The most commonly used measure is:

\text{Mean absolute percentage error: MAPE} = \text{mean}(|p_{t}|).

6 0
3 years ago
A truck can carry a load of 5000 lb. Assuming that it could be cut to fit, how many feet of steel beam weighing 32.6 lb/ft (poun
yKpoI14uk [10]

For this type of problem,

It is stated that the weight of steel is 32.6 lbs per foot

Meaning, every foot of steel beam weighs 32.6.

So 2 feet of steel beam would weigh 32.6 x 2 = 65.2 lbs

and 3 feet will be 32.6 x 3 = 97.8 lbs

Since we have a limit of 5000 lbs which is the capacity of the truck.

We can have an equation :

32.6x=5000

Where x is the number of foot

Solve the value of x by dividing both sides by 32.6 :

\begin{gathered} \frac{\cancel{32.6}x}{\cancel{32.6}}=\frac{5000}{32.6} \\ x=153.37ft \end{gathered}

So the answer is 153.37 feet of steel beam

3 0
1 year ago
8 divided by 618 ..............
ryzh [129]

Answer:

0.0129449838188

6 0
3 years ago
Read 2 more answers
HELP PLS <br><br> I’m rly confused
sasho [114]

bro use a photo math...................

5 0
3 years ago
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