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2 years ago

1. Find the distance and midpoint of XY when X(-7, 10) and Y(3, 4).

Mathematics

2 answers:

nordsb [41]2 years ago

6 0

I don’t know the answer

lutik1710 [3]2 years ago

5 0

Distance:

d = √(X2 - X1)² + (Y2 - Y1)²
d = √(3 -(-7))²+(4-10)²
d = √(3+7)²+(4-10)²
d = √(10)²+(-6)²
d = √100+36
d = √136
d ≈ 11.66

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KCCO, Inc., has current assets of $6,000, net fixed assets of $25,100, current liabilities of $4,950, and long-term debt of $12,

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We know that:

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3 years ago

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

$\frac{P_o}{168587.7} = \frac{600}{180}$

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=> $P_o = \$ 561958.9$

8 0

3 years ago