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2 years ago

Find the sum. 5(−3.4k−7)+(3k+21)

1 answer:

7 0

The answer should be -14 · (k + 1) if u simplify 17/5 and then rewrite the whole as a equivalent fraction and pull out like terms

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Can someone please solve this please.

Lelu [443]

Answer:

A≈576.31

Step-by-step explanation:

surface area = bh + L(s1+s2+s3)

surface area = (13*11) + 13 * (10+11+14.87)

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1 year ago

Help me, please<br> Which statement is true about the following pair of rectangles?

miv72 [106K]

Answer:

Step-by-step explanation:

$\frac{27}{33} = \frac{9}{11}$

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2 years ago

Please help me...I gotta get this right for my test. (15 points)

ss7ja [257]

Answer:

negative slope

Step-by-step explanation:

you have to subtract

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2 years ago

Read 2 more answers

PLEASE HELP I WILL HELP YOU

Sidana [21]

Answer:

5 is the answer

Step-by-step explanation:

hope this helps

7 0

1 year ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

2 years ago