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3 years ago

Find the sum. 5(−3.4k−7)+(3k+21)

1 answer:

7 0

The answer should be -14 · (k + 1) if u simplify 17/5 and then rewrite the whole as a equivalent fraction and pull out like terms

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zhenek [66]

Answer:

345x32=11040

546/7=78

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Step-by-step explanation:

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3 years ago

What is the value of y in the solution to the system of equations 5x-y=25 and x+4y=-10

Amiraneli [1.4K]

Answer:

y=-3.571

Step-by-step explanation:

To get rid of the x's make the other x cancel out the other.

5x-y=25+(-5(x+4y=-10)=-21y=75= -3.571

3 0

3 years ago

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kaheart [24]

Answer:15 candy bars are solddd

Step-by-step explanation:

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3 years ago

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What is the value of 15C2?

zaharov [31]

This is just 15 molecules of C2 or carbon dioxide

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3 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

<u>Answer:</u>

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

<u>Solution:</u>

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

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3 years ago