21(2-x)+12=44
multiply 21 by everything inside parentheses first
(21*2)+(21*-x)+12=44
42-21x+12=44
combine like terms
(42+12)-21x=44
54-21x=44
subtract 54 from both sides
-21x= -10
divide both sides by -21
negative divided by negative becomes positive
x= 0.476
Check:
substitute x=0.476 in equation
21(2-x)+12=44
21(2-0.476)+12= 44
21(1.524)+12= 44
32.004+12=44
44=44
Hope this helped! :)
The ratio is 4:9 to get from 4 to 36, you need to multiply 4 by 9. Now you need to do the same to 9. multiply 9x9 to get 81. The new ratio is 36:81, with 3 point tries being 81.
Hope this helped :)
<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>
1. ABCD is a quadrilateral in which AD=BC and ∠DAB=∠CBA (given)
2. AB = AB (reflexive property)
3. Triangles ABD and BAC are congruent (SAS)
<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>
4. BD=AC (corresponding sides of congruent triangles are equal)
<u>Part</u><u> </u><u>(</u><u>iii</u><u>)</u>
5. ∠ABD = ∠BAC (corresponding angles of congruent triangles are equal)
Let's look at the second equation and try multiplying it by 4:
4 * (3x + ky) = 4 * 27
Which gives us:
12x + 4ky = 108
This looks almost exactly like the first equation except that instead of -20y, there is 4ky. We could try making them equal to each other and solving for k:
-20y = 4ky
-20 = 4k
k = -5
Then, the answer is k = -5.
First lets see the pythagorean identities
So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is
Now we need to check the sign of sin theta
First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.
So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .
