Help me i need help ok try to explain and ok ok ok ok ok ok ok ok

Mathematics

1 answer:

Kaylis [27]2 years ago

7 0

Question 9

18, 28, 6, 54

Question 10

Correct Number: 5

Incorrect Number: 6

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20.) Which inequality represents the solution on the graph?*<br><br>

VMariaS [17]

Answer:

Option 2

Step-by-step explanation:

You can see that the graph of the inequality is x <= -3, so you want to find why inequality matches that. Solve each one:

. $3x \geq -9\\x \geq -3$

doesn't match

$-7x\geq 21\\x\leq -3$

Does match, so this is the answer.

7 0

3 years ago

Between which two rational numbers is squar root of 3 located

inessss [21]

We know that;

$1 ^{2} = 1 \\ 2^{2} = 4 \\ 

And 3 is between 1 and 4, therefore;\\ \boxed{1 \leq \sqrt{3} \leq 2 }

$

3 0

3 years ago

A certain change in a process for manufacture of component parts is being considered. Samples are taken using both the existing

Katyanochek1 [597]

Answer:

a) The confidence interval is $0.00\leq\pi_1-\pi_2\leq0.02$ .

Step-by-step explanation:

We have to calculate a confidence interval (CI) of a difference of proportions.

For the existing procedure, the proportion is:

$p_1=75/1500=0.05$

For the new procedure, the proportion is:

$p_2=80/2000=0.04$

To calculate the CI, we need to estimate the standard deviation

$s=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2} }\\\\s=\sqrt{\frac{0.05(1-0.05)}{1500} +\frac{0.04(1-0.04)}{2000} }=\sqrt{ 0.000032 + 0.000019 }=\sqrt{ 0.000051 }\\\\s=0.007$

For a 90% CI, the z-value is 1.64.

Then, the CI is:

$(p_1-p_2)-z*\sigma \leq\pi_1-\pi_2\leq(p_1-p_2)+z*\sigma \\\\(0.05-0.04)-1.64*0.007\leq\pi_1-\pi_2\leq(0.05-0.04)+1.64*0.007\\\\0.01-0.01\leq\pi_1-\pi_2\leq0.01+0.01\\\\0.00\leq\pi_1-\pi_2\leq0.02$