All categories

3 years ago

Find MN Segment addition postulate

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

7 0

Answer:

Step-by-step explanation:

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$

You might be interested in

Write the equation of the line that contains the given point and the given slope. (-46,45), slope=2.5 please help and explain

Elis [28]

Answer:

y = 2.5x + 160

Step-by-step explanation:

b = 45 - (2.5)*(-46)

b = 45 + 160

b = 205

3 0

3 years ago

Read 2 more answers

PLESE ANSWE ASAPPPPP

Ket [755]

Answer:

Number of terms: 2

Degree: 1

Step-by-step explanation:

✔️A term can either be a coefficient with a variable, a variable, or a constant.

In the polynomial given, 10y + 2, there are two terms:

First term is a coefficient with a variable = 10y

Second term is a constant = 2

The two terms are: 10y and 2

✔️Degree of a polynomial is the highest exponents possessed by any of its term.

10y has an exponent of 1.

The degree of the polynomial therefore will be 1

7 0

3 years ago

What is f(x)= (x-3)(x+4) in standard form?

ANEK [815]

Answer:

The answer for this problem is x^2+x-12

7 0

3 years ago

(6x^3 + 4x^2 + 2x) ÷ 2x Answer fast plz..

Phoenix [80]

refer to the attachment okay

mark me a brainlist answer I need only 1

3 0

3 years ago

Read 2 more answers

The dimensions of a rectangular garden were 4m by 5m. Each dimension was increased by the same amount the garden then had an are

pogonyaev

The dimension of new garden is 7 meter by 8 meter

Solution:

The dimensions of a rectangular garden were 4m by 5m

Length = 4 m

Width = 5 m

Each dimension was increased by the same amount the garden then had an area of 56 square meter

Let "x" be the amount of increase

Then,

Length = 4 + x

Width = 5 + x

Also, given that,

New area = 56 square meter

The area of rectangle is given as:

$Area = length \times width$

Substituting the values we get,

$56 = (4+x)(5+x)\\\\56 = 20 + 4x + 5x + x^2\\\\x^2 + 9x + 20 - 56 = 0\\\\x^2 + 9x -36=0$

Let us solve the above equation by quadratic formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{For } x^2+9x-36 \text{ we get , }$

a = 1 and b = 9 and c = -36

Substituting the values of a = 1 ; b = 9 ; c = -36 in above quadratic formula we get,

$x = \frac{-9\pm \sqrt{9^2-4\cdot \:1\left(-36\right)}}{2\cdot \:1}\\\\x = \frac{-9\pm \sqrt{81+144}}{2}\\\\x = \frac{-9 \pm 15}{2}$

We get two solutions,

$x = \frac{-9+15}{2} \text{ or } x = \frac{-9-15}{2}\\\\x = 3 \text{ or } x = -12$

Since dimension cannot be negative, ignore x = -12

Thus solution is x = 3

Length = 4 + x = 4 + 3 = 7

Width = 5 + x = 5 + 3 = 8

Thus dimension of new garden is 7 meter by 8 meter

5 0

3 years ago