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sineoko [7]
3 years ago
10

Samantha is multiplying 832.63 by 0.1. Which statement is true about the product? A. It will be less than 832.63. B. It will be

greater than 832.63. C. It will be equal to 832.63.
Mathematics
1 answer:
sladkih [1.3K]3 years ago
7 0
The answer for your question es C
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Please help me with this. Use the combination method of substitution to solve. Please show and explain work. Thanks.
Artemon [7]

Answer:

x = 25.35 (or 2129/84) and y = 4334.04 (or 121353/28)

Step-by-step explanation:

The given equations are set up and ready to go with substitution. Simply just plug in the first equation to the second equation as both are equal to y.

Step 1: Replace y in <em>y = 87x + 2129 </em>with <em>171x</em>

171x = 87x + 2129

Step 2: Subtract 87 x on both sides

84x = 2129

Step 3: Divide both sides by 84 to get x

x = 2129/84 or 25.35 (rounded)

To get y, simply plug in x into one of the 2 original equations. In this case, I will use the first equation:

y = 171 (25.35)

y = 121353/28 or 4334.04 (rounded)

You can check your work by plugging both solutions into the calculator and see if they equal each other. The values for these answers are solely based on the equations, so if you write the <em>equations </em>wrong themselves, then that means you have the values wrong as well.

6 0
3 years ago
"The product of four and a<br> number is more than ten."<br> ( write as an inequality thx)
lubasha [3.4K]

Answer:

4x > 10

Step-by-step explanation:

4x > 10

6 0
3 years ago
Which of these are proportional?!?!
sergiy2304 [10]
The first is proportional the second is proportional and the third is not proportional
3 0
3 years ago
ryan takes a 30 centimeter by 72 centimeter sheet of paper and cuts from one corner of the paper to diagonally opposite corner.
nikklg [1K]

Answer:

178

Step-by-step explanation:

Use Pythagorean Theorem to find the Hypotenuse

30^2+72^2=78^2

Use perimeter formula

a+b+c

38+72+30

3 0
3 years ago
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4/6 chance or 2/3 chance. i’m not sure if this is like probability i’m at a middle school level
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