Answer:
,
Step-by-step explanation:
Here a=1, b=2 and c=8
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Ration expressions cause excluded values wherever the denominator equals zero.
So, for any expression like
-5 is an excluded value if
For example, the simplest one would be
In fact, if you try to evaluate this function at -5, you'd have
which is undefined, and thus you can't evaluate the function, and thus -5 is an excluded value.
Answer:
it is b. she will have 99 bucks.
Since dividing fractions are not possible, you must first find the reciprocal of 6/1 which is 1/6. And the equation would be written as 3/4*1/6. Cross cancel the 3 and 6 leaving 1/4*1/2=1/8. Thus, your answer is lowest terms is, 1/8.