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german
2 years ago
6

2x^2(6x^3-3x+1) need help

Mathematics
1 answer:
bazaltina [42]2 years ago
5 0

2

2

(

6

3

−

3

+

1

)

2

x

2

(

6

x

3

−

3

x

+

1

)

2x2(6x3−3x+1)

Simplify

1

Distribute

2

2

(

6

3

−

3

+

1

)

2

x

2

(

6

x

3

−

3

x

+

1

)

2x2(6x3−3x+1)

1

2

5

−

6

3

+

2

2

12

x

5

−

6

x

3

+

2

x

2

12x5−6x3+2x2

Solution

1

2

5

−

6

3

+

2

2

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Answer:

x^2+1/x^2

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Step-by-step explanation:

6 0
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Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

3 0
3 years ago
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Answer:

2

Step-by-step explanation:

6x=4+8

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ad-work [718]

Answer:

23

Step-by-step explanation:

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