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GaryK [48]
3 years ago
5

-2x > -10 solve for x

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
5 0

Answer:  X < 5

Step-by-step explanation:

Korvikt [17]3 years ago
4 0

Answer:

x<5

Step-by-step explanation:

View Picture

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Nesterboy [21]

Answer:

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4 0
3 years ago
How do the arrows for +1 and -1 show both distance and direction?
Fofino [41]
By the way the arrow is pointing?
3 0
3 years ago
A scale drawing of a rectangular park had a scale of 1 cm = 100 m.
Brilliant_brown [7]

Answer:

521,400 meters squared

Step-by-step explanation:

With the 1cm = 100m scale

6.6 cm = 660m

7.9 cm = 790m

Area = 660 x 790 = 521,400 meters squared

7 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0
3 years ago
Will give brainlest if right! Two plus two?
Temka [501]
4??? fish??? if it's a trick question, then the answer is probably fish :o)
4 0
3 years ago
Read 2 more answers
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