The Bugatti have the fastest soles
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
We know that y is equal to x-2. We can just substitute x-2 for y since y is equal to it.
10x- 9(x-2)=24
Distribute.
10x- 9x+18= 24
x+18= 24
Subtract 18 on both sides.
x= 6
Now, plug in x.
y= (6)-2
y= 4
We can check this to see if this works:
4= 6-2, 4=4
10(6)- 9(4)= 24
60-36= 24, 24=24
x=6 and y=4
I hope this helps!
<em>~kaikers</em>
Answer:
1, 13, 5 are correct
Step-by-step explanation:
