A, Is the answer according to my calculations.
162/(6(7-4)^2)
pemdas
parenthasees inner first
so 7-4 is forst
7-4=3
162/(6(3)^2)
then exponents
3^2=9
162/(6(9))
multiplication
6 times 9=54
162/(54)=3
The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
She can buy maximum of
packages while staying within her budget.
Minimum spending limit
$
.
Maximum spending limit
$
.
Cost of one package of beads
$
.
Number of packages of beads bought
.
Cost of one package of charms
$
.
Let the number of packages of beads bought be
.








So, she can buy maximum of
packages while staying within her budget.
Learn more about solving inequalities here:
brainly.com/question/12189350?referrer=searchResults
It’s similar to D because they are going to have the same measured angle