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Rama09 [41]
3 years ago
15

Thomas has 3 boxes, each with 8 balls.

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

6 ball will be in each of the 4 boxes

Step-by-step explanation:

because if we do 8 multiply 3 equal to 24

And if we do 24 divide 4 equal to 6

marin [14]3 years ago
5 0

Answer: 6 balls will be in each of the 4 boxes.

Step-by-step explanation:

Multiply 3x8 to find out how many balls there are total.

3x8=24

Then to split them evenly, you divide by 4 (the amount of boxes they are split into)

24/4= 6

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Is w^2-9w+81 a trinomial square
Yuri [45]
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
( \sqrt{a}x+ \sqrt{c})^{2} or ( \sqrt{a}x- \sqrt{c})^{2}
so
if w^2-9w+81 is perfect square, factored form is either
( \sqrt{1}x+ \sqrt{81})^{2} or ( \sqrt{1}x- \sqrt{81})^{2}  aka ( x+9)^{2} or  ( x-9)^{2}
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not






8 0
3 years ago
I need the answer ASAP
GalinKa [24]

Answer:

the answer is A

Hope it helps

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3 years ago
What is an I'm proper fraction in math? Sorry I am doing Aleks I can give yuh my usewrname and pw if yuh need it bc it don't kno
antiseptic1488 [7]
A proper fraction<span> is a </span>fraction<span> where the numerator (the top number) is less than the denominator</span>
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3 years ago
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What’s the name for excessive bodily hair growth in women?
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6 0
3 years ago
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The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
jeyben [28]

Answer:

The period of Y increases by a factor of k^ {3/2} with respect to the period of X

Step-by-step explanation:

The equation T ^ 2 = a ^ 3 shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?  

For the planet Y:  

T_y ^ 2 = a_y ^ 3

For planet X:  

T_x ^ 2 = a_x ^ 3

To know the factor of aumeto we compared T_x with T_y

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:  

a_y ^ 3 = (a_xk) ^ 3

So

\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x

Then, the period of Y increases by a factor of k^ {3/2} with respect to the period of X



4 0
3 years ago
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