If you were to rotate the flag to the right you will see that the inside seams of the shadow box are the same length as the edges of the folded flag. Meaning that if we were to just consider the length measurements of the folded flag then the flag would fit. However, we are also given the degree of which the point of the flag is folded, so we need to make sure that matches with the degree angle of the shadow box. The angles are the same therefore the folded flag should fit perfectly into the shadow box.
When tow solids of similar shape that is assuming to be a box in this case, having a length ratio of 2:9, we get the ratio of the surface areas equal to the<span>square of the ratio of their edges. This is becaue the surface area is equal to the area of the base (square) which is the square of the side. Answer is B.</span>
We have 8 sides to calculate, it will be hard to explain which side I'm calculating without marking on the picture.
We will start with the front facing side. We can break this up into an 8ft x 8ft square, and a 14ft x 6ft rectangle. The area equals:
8ft x 8ft + 14ft x 6ft = 148ft^2
The front facing is the same area as is back facing counterpart so we can multiply the surface area by 2:
148ft^2 x 2 = 296f^2
Adding the bottom surface area 6ft x 14ft:
6ft x 14ft + 296ft^2 = 380ft^2
Adding the right side 6ft x 14ft:
6ft x 14ft + 380ft^2 = 464ft^2
Adding the left side 8ft x 6ft:
8ft x 6ft + 464ft^2 = 512ft^2
Adding the 3 sides on the top 8ft x 6ft (top facing), 6ft x 6ft (top facing), and 6ft x 6ft (left facing):
<span>8ft x 6ft + 512ft^2 = 560ft^2
</span><span>6ft x 6ft + 560ft^2 = 596ft^2
</span>6ft x 6ft + <span>596</span>ft^2 = 632ft^2
Therefore the answer is C, 632 ft^2.
30mx + my + 2nx +ny
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15nx - 2my + nx -2ny
