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podryga [215]
3 years ago
7

Two planes start from the same point and fly opposite directions. The first plane is flying 20 mph slower than the second plane

in 2 h the planes are 540 mi apart. Find the rate of each plane
Mathematics
2 answers:
alexira [117]3 years ago
5 0

Answer:

4x+50=470

4x=420

x=105 mph First plane

x+25= 105+25=130 mph Second plane.

R^2

Step-by-step explanation:

UNO [17]3 years ago
4 0

Answer:

This

Step-by-step explanation:

let x = rate of the slower plane (First plane!)

x+25 = rate of the faster plane (Second plane!)

The planes fly for 2 hours, where Distance = R*T

Distance between the planes = SUM of the distances.

R*T + R*T= 470 miles

2*x + 2*(x+25)=470

2x+2x + 50 = 470

4x+50=470

4x=420

x=105 mph First plane

x+25= 105+25=130 mph Second plane.

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“a railroad bridge spans a gorge 40 feet wide and connects two cliffs at heights of 98 and 158 feet above the bottom of the gorg
VMariaS [17]

Answer:

Height above the bottom gorge is 113 feet

Step-by-step explanation:

The width of the gorge = 40 feet

The height of the higher cliff = 158 feet

The height of the lower cliff = 98 feet

The length of the bridge = √((158-98)² + 40²) = 72.11 feet

The slope of the bridge = (158-98)/40 = 1.5

The length of 1/4 of the bridge from the lower cliff =72.11 - 3/4×72.11 = 18.03 feet

The angle of inclination of the bridge = tan⁻¹(1.5) = 56.31°

The height above the bottom at 3/4 from the higher cliff = The height above the bottom at 1/4 from the lower cliff = 98+ 18.03×sin(56.31 ) = 113 feet

Which can also be found directly from the heights of the two cliffs knowing that 3/4 from the higher cliff = 1/4 from the lower cliff giving;

Height above the bottom gorge = 98 + 1/4×(158 - 98) = 113 feet.

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Read 2 more answers
The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

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