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podryga [215]
3 years ago
7

Two planes start from the same point and fly opposite directions. The first plane is flying 20 mph slower than the second plane

in 2 h the planes are 540 mi apart. Find the rate of each plane
Mathematics
2 answers:
alexira [117]3 years ago
5 0

Answer:

4x+50=470

4x=420

x=105 mph First plane

x+25= 105+25=130 mph Second plane.

R^2

Step-by-step explanation:

UNO [17]3 years ago
4 0

Answer:

This

Step-by-step explanation:

let x = rate of the slower plane (First plane!)

x+25 = rate of the faster plane (Second plane!)

The planes fly for 2 hours, where Distance = R*T

Distance between the planes = SUM of the distances.

R*T + R*T= 470 miles

2*x + 2*(x+25)=470

2x+2x + 50 = 470

4x+50=470

4x=420

x=105 mph First plane

x+25= 105+25=130 mph Second plane.

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Answer:

1. Use the Adjacent and opposite side (Ignore the Hypotenuse)

Or use HERO'S FORMULA based on the information given

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Step-by-step explanation:

There are three to four ways we can go about finding the area of a triangle. And a these would be dependent on the information given about the triangle.

From the question, you said the three side lengths are given. In such case, we employ the HERO FORMULA.

HERO FORMULA:

Area = √ s(s-a)(s-b)(s-c)

where s = 1/2(a + b + c)

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But since the question insisted that we use 1/2* base * height. Let's use our know of right angle to dissolve that.

A right angle triangle has three sides. The longest is always the Hypotenuse.

Let's take it this way.

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Area = 1/2 * 18 * 24

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Step-by-step explanation:

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