Two planes start from the same point and fly opposite directions. The first plane is flying 20 mph slower than the second plane
in 2 h the planes are 540 mi apart. Find the rate of each plane
2 answers:
Answer:
4x+50=470
4x=420
x=105 mph First plane
x+25= 105+25=130 mph Second plane.
R^2
Step-by-step explanation:
Answer:
This
Step-by-step explanation:
let x = rate of the slower plane (First plane!)
x+25 = rate of the faster plane (Second plane!)
The planes fly for 2 hours, where Distance = R*T
Distance between the planes = SUM of the distances.
R*T + R*T= 470 miles
2*x + 2*(x+25)=470
2x+2x + 50 = 470
4x+50=470
4x=420
x=105 mph First plane
x+25= 105+25=130 mph Second plane.
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23/50 is 0.46 so the percentage would be 46%
D because it would 44 below since 4 times 7 = 28 so it would switch over for to 6 times 7 =44
What is the question that is being asked?
Answer:
50 points
Step-by-step explanation:
i looked it up, and the internet says 46 is 92% of 50.
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7 goes into 6,300 900 times so your answer is 6,300
