C im pretty sure thats it
Answer:
a) 70 azulejos
b) 37500 litros
c) 37.5m³
Step-by-step explanation:
A piscina tem 5 m de comprimento, 3 m de largura e 2,5 m de profundidade.
Comprimento = 5m
Largura = 3m
Profundidade (altura) = 2,5 m
Calcular:
a) A quantidade de ladrilhos necessária para cobrir a piscina
Isso é calculado como a área de superfície da votação
A = 2 (wl + hl + hw)
A = 2 × (3 × 5 + 2.5 × 5 +2.5 × 3)
A = 70 m²
Observe que:
1 m² = 1 azulejo
70 m² = 70 azulejos
b) A quantidade de água que pode caber na piscina.
1 m³ = 1000 litres
O volume de uma piscina = Comprimento × Largura × Altura
= 5m × 3m × 2.5m
= 37.5m³
1 m³ = 1000 litros
37.5m³ =
37.5 × 1000 litros
= 37500 litros
c) seu volume em m³
O volume de uma piscina = Comprimento × Largura × Altura
= 5m × 3m × 2.5m
= 37.5m³
Answer:
The correct number of basic operations that exist in mathematics is four (addition, subtraction, multiplication and division) because the definition of an operation is the carrying out of a task by the application of principles and these four operation are arithmetic operations that have precedence rules or order of operations, such that we must first multiply or divide before adding or subtracting
Division is different from simply multiplying by a fraction because in Euclidean division, the result is a quotient and a remainder, which shows that division can yield more than one result while multiplication yields a single result
For subtraction and addition, one of the differences is that subtraction cannot be simply commuted
a - b = -(b - a)
Subtraction is non-associative;
a - b - c when arranged as (a - b) - c and a - (b - c), can yield different results depending on operation order which is unlike addition
Therefore, the four basic operations in mathematics are addition, subtraction, multiplication and division
Step-by-step explanation:
Answer:
<u>1/7=3/21</u>
<u>7/1=21/3</u>
the other fractions are not correct/valid therefore the fractions above are the correct answers
Step-by-step explanation:
Let me know if you need any other help:)