Please help me with this, it’s my final exam i will mark as brainliest

PLEASE HELP ME THIS IS DUE ASAP!!! I will mark brainliest if right!!! Explain!

Fed [463]

Answer:

Step-by-step explanation:

6 0

3 years ago

Compare adding unlike fractions and adding like fractions

muminat

Answer:

We just add numerators and rewrite denominator.

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

Step-by-step explanation:

You mean unlike denominators and like denominators.

Adding like dominators: We just add numerators and rewrite denominator :

Example : $\frac{1}{4} +\frac{2}{4}=\frac{1+2}{4} =\frac{3}{4}$

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

For example :

$\frac{1}{5}+\frac{3}{4}$

LCM for 5 and 4 is 20 : Now, divide by 5 and multiply by 1 for first fraction. 20 divide by 4 and multiply by 3 :

$\frac{1*4}{20} +\frac{3*5}{20}=\frac{4}{20} +\frac{15}{20}=\frac{19}{20}$

4 0

3 years ago

Read 2 more answers

In 1934 there was an extreme drought and the Great Plains and the number 1,934 is the value of the nine and the hundredth place

WARRIOR [948]

It should be noted that No. the value of the 9 in the hundred place is not ten times the value of 3 in the tens place.

<h3>How to illustrate the information?</h3>

It should be noted that the value of 3 in 1934 is 30 and the value of 9 is 900.

1934 = 1000 + 900 + 30 + 4

Therefore the value of 9 will be:

= 30 × 3

Therefore, the the value of the 9 in the hundred place is 30 times the value of 3 in the tens place.

Learn more about place values on:

brainly.com/question/2041524

#SPJ1

5 0

2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago

Y=−2x+7<br> y=5x−7<br><br> x=<br> y=<br>

WINSTONCH [101]

Answer:

x = 2

y = 3

Explanation:

3 0

2 years ago