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aliina [53]
3 years ago
9

PLS HELP WILL MARK BRAINLIEST. IF GOTTEN RIGHT SHOW WORK

Mathematics
1 answer:
zalisa [80]3 years ago
3 0

9514 1404 393

Answer:

  12 feet

Step-by-step explanation:

You seem to have a few of these, so let's find a generic solution.

The vertex form of a quadratic equation is ...

  f(x) = a(x -h)² +k

When we expand that, we get ...

  f(x) = a(x² -2hx +h²) +k = ax² -2ahx +ah² +k

Comparing this to your standard form quadratic ...

  h(t) = -16t² +vx +s

we can see that ...

  • a = -16
  • -2ah = v
  • ah² +k = s

Solving for h and k, we get ...

  (-2)(-16)h = v

  h = v/32

and

  k = s -ah² = s -(-16)(v/32)²

  k = s +v²/64

So, the generic solution for these problems is ...

  h = time to maximum height = v/32

  k = maximum height = s +v²/64

__

This problem asks for the maximum height, which will be ...

  s +v²/64 = 3 +24²/64 = 3 +9 = 12 . . . . feet

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