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aliina [53]
3 years ago
9

PLS HELP WILL MARK BRAINLIEST. IF GOTTEN RIGHT SHOW WORK

Mathematics
1 answer:
zalisa [80]3 years ago
3 0

9514 1404 393

Answer:

  12 feet

Step-by-step explanation:

You seem to have a few of these, so let's find a generic solution.

The vertex form of a quadratic equation is ...

  f(x) = a(x -h)² +k

When we expand that, we get ...

  f(x) = a(x² -2hx +h²) +k = ax² -2ahx +ah² +k

Comparing this to your standard form quadratic ...

  h(t) = -16t² +vx +s

we can see that ...

  • a = -16
  • -2ah = v
  • ah² +k = s

Solving for h and k, we get ...

  (-2)(-16)h = v

  h = v/32

and

  k = s -ah² = s -(-16)(v/32)²

  k = s +v²/64

So, the generic solution for these problems is ...

  h = time to maximum height = v/32

  k = maximum height = s +v²/64

__

This problem asks for the maximum height, which will be ...

  s +v²/64 = 3 +24²/64 = 3 +9 = 12 . . . . feet

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Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59

Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm

Given that the density of air at room temperature is 0.00118g/cm^3, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg

Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
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