

Substitute 51/5x into

Substitute that into

Hope this helps. Answer should be correct. Unless your quadratic equation is wrongly stated.
Answer:
My answers:
1. p = 0.20 × 100 × k
4. y = 1.25x + 3; $8.00
Step-by-step explanation:
your welcome
Answer/Step-by-step explanation:
Note:
<u>Graphing From An Equation: </u>
Equation are frequently written in slope-intercept form { y = mx+b}.
Which "m" represents the slope and "b" represents the y-intercept.
<u>Solutions and Equation:</u>
Solutions to linear equations contain any points located on the graphed line.
Ordered Pair = Solution to an equation if it's values are substituted in the equation which makes it true
Solve:
{x = 0 } 3(0) - 4y = 12
-4y = 12 (0, -3 )
-4y/-4 = 12/-4
y = -3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
{y = 0} 3x-4(0) =12
3x = 12 (4,0)
3x/3 = 12/3
x = 4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
<u><em>~Lenvy~</em></u>
When using the Internet to conduct consumer research, be sure to use reliable websites, verify sources and know the purpose. So the answer is letter D. All of these.
Answer:
The correct order is:
a
c
d
b
Step-by-step explanation:
First, let's write 1/x in a convenient way for us:
a) Substitute 1/x = p/q, to obtain x = 1/(1/x) = 1/(p/q) = q/p.
Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:
c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.
Now we know that we can write x as a quotient of two integers, we need to imply that, then the next one is:
d) Observe that x is the quotient of two integers with the denominator nonzero.
And that is the definition of rational, then we end with:
b) Hence x is rational.
Which is what we wanted to get.