Ac method
for
ax^2+bx+c
multiply a and c together
find what 2 numbers multiply to get ac and add to get b
split b up
gropu
factor
3x^2+7x+2
2 times 3=6
what 2 numbers multily to get 6 and ad to get 7
6 and 1
3x^2+6x+1x+2
(3x^2+6x)+(1x+2)
3x(x+2)+1(x+2)
(3x+1)(x+2) is factored
Sequence: -4, 8, -16
rate of increase: -16/8 = -2
If you make A1 the first term in the sequence you must use (n-1) in the explicit formula. If you go backwards in the sequence to find A0 = 2 then you would use n.
The don't have A0 = 2 listed as an option so we use A1 = -4 and (n-1) terms.
An = -4(-2)^(n-1)
Solving for the 5th term A5, use n = 5
A5 = -4(-2)^(5-1)
A5 = -4(16)
A5 = -64
So the answer is B.
Turn y - 4 = -2/3(x - 6) into a linear equation.
y - 4 = -2/3(x - 6)
y - 4 = -2/3x + 4
+4 +4
y = -2/3x + 8
The equation that is perpendicular to y = -2/3x + 8 is y = 3x + 4 as shown in the image below using a graph.
Step-by-step explanation:
Given,
x = y - 3
Also,
6(y - 3) = 3y + 6
6y - 18 = 3y + 6
6y - 3y = 6 + 18
3y = 24
y = 24/3
y = 8
x = 8 - 3
x = 5
Therefore, the first number is 5 and the second number is 8.
Answer:
<h2>3 months</h2>
Step-by-step explanation:
