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N76 [4]
4 years ago
15

Which statement best summarizes Ella’s work? Ella’s procedure and conclusion are correct. Ella’s procedure is correct, but her c

onclusion is incorrect. Ella’s procedure is incorrect, but her conclusion is correct. Ella’s procedure and conclusion are incorrect.
Mathematics
2 answers:
const2013 [10]4 years ago
8 0

Answer:

The correct answer is D

Step-by-step explanation:

i got it correct on Edg ;D

muminat4 years ago
5 0

Answer:

The Answer is D

Step-by-step explanation:

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Which expression is equivalent to x^-5/3<br><br> Answer choices:
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1/3x5 the Answer is b

Step-by-step explanation:

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If you were to add 12.52, 349.0 and 8.24, how many significant digits should the answer have? a.. three. c.. five. b.. four. d..
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<span>b.. four
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fred's auto sales purchases 3 new vehicles for $11,219, $31,611, and $18,204. what was the total cost for all the vehicles?
Anarel [89]
Add them all together = $61034
8 0
3 years ago
I need help please..... i really do need it
shepuryov [24]

Answer:

Sarah = 78

Lee = 79

Step-by-step explanation:

98   +   100   +   65   +   78   +   98   +   46   +   100   +   100   +   45   +   50 = 780

780÷10= 78

97   +   67   +   89   +   99   +   100   +   45   +   79   +   89   +   58   +   67 =‬

790

790÷10=79

5 0
4 years ago
Read 2 more answers
A boat sails directly toward a 250-m skyscraper that stands on the
bazaltina [42]

a) The value of  \theta as a function of "x" is \theta = tan^{-1}\frac{250}{x}

b) The rate of change of the angle with respect to x is -0.000308rad/m

Find the complete question and diagram attached

Form the right-angled triangle shown:

Adjacent side = x

Opposite side = 250m

angle of elevation  = \theta

Using the SOH CAH TOA identity

tan\theta = \frac{opposite}{hypotenuse} \\tan \theta = \frac{250}{x} \\\theta = tan^{-1}\frac{250}{x}

Hence the value of  \theta as a function of "x" is \theta = tan^{-1}\frac{250}{x}

b) If x = 450m

\theta = tan^{-1}\frac{250}{x}\\tan \theta = \frac{250}{x}\\

Differentiate both sides with respect to "x"

sec^2 \theta \frac{d\theta}{dx} = \frac{-250}{x^2}  \\ \frac{d\theta}{dx} =  \frac{1}{sec^2\theta} \times \frac{-250}{x^2}

Substitute x = 450m and \theta = 60^0 into the resulting expression to have:

\frac{d\theta}{dx} =  \frac{1}{sec^260^0} \times \frac{-250}{450^2}\\\frac{d\theta}{dx} =  (cos60)^2\times \frac{-250}{202,500}\\\frac{d\theta}{dx} = 0.5^2\times \frac{-250}{202,500}\\\frac{d\theta}{dx} =-0.000308

Hence the rate of change of the angle with respect to x is -0.000308rad/m

Learn more here: brainly.com/question/15580615

3 0
3 years ago
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