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wlad13 [49]
3 years ago
12

Please solve my difficult question fast​

Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

The 3 angles form the straight line AB. A straight line equals 180 degrees.

The 3 angles when added together need to equal 180:

2x + 65 + (x + 65) = 180

Simplify by combining like terms:

3x + 130 = 180

Subtract 130 from both sides

3x = 50

Divide both sides by 3

X = 50/3

X = 16 2/3 (16.66667 as a repeating decimal)

Now you have x if you need to solve all the angles replace x with its value and sole:

2x = 2(16 2/3) = 33 1/3

X + 65 = 16 2/3 + 65 = 81 2/3

tatyana61 [14]3 years ago
7 0

Step-by-step explanation:

2x+65°+(x+65°)=180° ( sum of angle of straight angle )

3x+65°+65°=180°

3x=180°-130°

3x= 50°

now,

i) 2x=2*50=100°

ii) (x+65°) = 50+65 =115°

plz mark me brainiest and thanks

have a good day ahead...

(-_-)

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A rectangular prism had a volume of 252 cubic centimeters. The length of the prism is 14 centimeters and the width of the prism
mojhsa [17]
<h2>Answer:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. A rectangular prism is a solid whose base is a rectangle. Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

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In fact, the volume is 252cm^3 because:

V=14\times 6\times 3 \therefore V=252cm^3

Now the height of the prism was changed from 3 centimeters to 6 centimeters to create a new rectangular prism, therefore:

FOR THE NEW PRISM WE HAVE THE FOLLOWING DIMENSIONS:

L=14cm \\ \\ W=6cm \\ \\ H=6cm

So the new volume is:

V=14\times 6\times 6 \therefore V=504cm^3

<h3><em>What do we know about the volume of the new prism?</em></h3>

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Step-by-step explanation:

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Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

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The derivative of the volume as a function of radius is:

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Then, the change in volume is expanded:

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If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

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The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

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