Answer:
f^-1 (x) = 1+ln( (x-3)/2)
Step-by-step explanation:
hello :
let f(x) = y so : y = 2e^(x-1) +3
calculate x : e^(x-1) = (y-3)/2
for : y-3 > 0 : x-1 = ln( (y-3)/2) so : x= 1+ln( (y-3)/2)
If(x)= 2e^(x-1) +3 , what is f^-1 (x) = 1+ln( (x-3)/2)
Answer:
after 10 years there will be $600000 in my account
Y = 5x + 5
y - x = 5
You can use substitution to solve this system. Use y's expression (5x + 5) for y in the second equation to solve for x:
y - x = 5
5x + 5 + x = 5
6x + 5 = 5
6x = 0
x = 0
Substitute your value for x into one of the original equations to y:
y = 5x + 5
y = 5(0) + 5
y = 5
Finally, substitute both values into both original equations to check your work:
5 = 5(0) + 5 --> 5 = 5 <--True
5 - 0 = 5 --> 5 = 5 <--True
Answer:
x = 0
y = 5
Answer:
Step-by-step explanation:
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