Based on the total number of people who want the steakhouse option, the probability that a student will not want the seafoodbuffet if they want the steakhouse option is 24%
<h3>What is the probability of the students' choice?</h3><h3 />
The probability that a student does not want the seafood buffet given that they want the steakhouse option is:
= Number of people who want steakhouse but not seafood / Total surveyed
Solving gives:
= 9 / (16 + 8 + 9 + 4)
= 9 / 37
= 24%
Full question is:
If a student wants the steakhouse option, what is the probability that they will not want the seafoodbuffet?
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Answer:
The answer is B :) hope you have a great day
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Answer:
A.0.4477
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected exam will require between 14 and 19 minutes to grade?
This probability is the pvalue of Z when X = 19 subtracted by the pvalue of Z when X = 14. So
X = 19



has a pvalue of 0.7389.
X = 14



has a pvalue of 0.2912
0.7389 - 0.2912 = 0.4477
So the correct answer is:
A.0.4477
<span>(6c2) * (10c6) * (3c2)
Multiply
60c8 * 3c2
Multiply again
Final Answer: 180c10</span>