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siniylev [52]
3 years ago
5

Alguien que sepa cómo se resuelve ésto que me ayudé a solucionarlo,es urgente,doy 25 puntos

Mathematics
1 answer:
mash [69]3 years ago
4 0

38 42 34 54

Step-by-step explanation:

7have the best mayonnaise bianco babi naive albino pig is this real or not be a posible and I am a great day for 53feet

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On Sunday, a local hamburger shop sold a combined total of 378 hamburgers and cheeseburgers. The number of cheeseburgers was sol
ipn [44]

Answer:

The number of hamburgers sold was 126.

Step-by-step explanation:

Let h = number of hamburgers sold

let c = cheeseburgers sold

c+h = 378

c = 2h

Substitute c =2h into c+h =278

c+h =378

2h+h = 378

Combine like terms

3h = 378

Divide by 3

3h/3 =378/3

h =126

The number of hamburgers sold was 126.

5 0
3 years ago
One factor of this polynomial is (2x - 1). Use long division to determine which expression represents the other factor. 2x³+ 5x²
rusak2 [61]

-> 3rd answer is correct

6 0
2 years ago
Help Pleaseeee. Find the hypotenuse.
ivann1987 [24]

I don't because I can't see

8 0
3 years ago
A basketball player shoots the ball with an initial velocity of 17.1 ft/sec at an angle of 45.6 degrees with the horizontal.to t
jeka94
The horizontal component is:

17.1cos45.6≈11.96 so

vx=12.0 ft/sec  (to nearest tenth ft/s)
3 0
3 years ago
Read 2 more answers
A piece of wire 28 ft long is cut into two pieces. One piece is used to form a square, and the remaining piece is used to form a
marusya05 [52]

Answer:

Wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

Step-by-step explanation:

Length of the wire = 28 ft has been cut in two pieces.

One piece is used to form a square and remaining piece to form a circle.

Let the length of the wire which forms the square is 'l' ft.

Area of the square = (side)²

Perimeter of the square = 4(side) = l

Length of one side = \frac{l}{4}

So, the area of the square = \frac{l^{2}}{16} ft²

Now length of the remaining part = perimeter of the circle = (28 - l) ft

2πr = (28 - l)

r = \frac{28-l}{2\pi }

Area of the circle formed = πr²

= \frac{\pi(28-l)^{2} }{4(\pi )^{2} }

= \frac{(28-l)^{2}}{4\pi }

Combined area of the square and circle

= \frac{l^{2}}{16} + \frac{(28-l)^{2}}{4\pi }

= \frac{l^{2}}{16} + \frac{(28-l)^{2}}{4\pi }

Now to maximize the area we will find the derivative of the area with respect to l.

\frac{dA}{dl}=\frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28-l)^{2}}{4\pi}]

= \frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28)^{2}+l^{2}-56l }{4\pi }]

= \frac{2l}{16}+\frac{(2l-56)}{4\pi }

Now equate the derivative to zero.

\frac{2l}{16}+\frac{(2l-56)}{4\pi } = 0

(2l-56)=-\frac{2l}{16}\times 4\pi

(2l-56)=-\frac{\pi l}{2}

2l+\frac{\pi l}{2}=56

\frac{(4l+l\pi )}{2}=56

l(4 + π) = 112

l(4 + 3.14) = 112

l = \frac{112}{7.14}

l = 15.69 ft

Length of the other part = 28 - 15.69 = 12.31 ft

Therefore, wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

8 0
3 years ago
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