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Rzqust [24]
2 years ago
9

You are offered two jobs. One with a yearly salary of $51,670, and the other an hourly

Mathematics
1 answer:
sattari [20]2 years ago
5 0

Step-by-step explanation:

a year = 52 weeks

a year working hours = 45× 52 = 2340 hours

first job rate per hour = $51670 ÷ 2340 hours

= $22

sec job rate per hour = $26

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Step 1: d+3 &lt; 1 <br><br> Step 2: b+6&lt; 9
In-s [12.5K]

Answer:

1) d < -2

2) b < 3

Step-by-step explanation:

1) d+3< 1

subtract both sides by 3

d+3 -3 < 1-3

d<-2

2) b+6< 9

subtract both sides by 6

b+6 -6 < 9 -6

b< 3

3 0
2 years ago
I need help assap
Bad White [126]
It’s 2=x because you have start with 2 then 5
5 0
2 years ago
a 400 g of a liquid of density 1.6g/cm3 is made from mixing liquids of density 1.2g/cm3 and 1.8g/cm3 find the mass of the liquid
gogolik [260]

Answer:

133.33g

Step-by-step explanation:

Let the:

Mass of 1.2g/cm³ of liquid = x

Mass of 1.8g/cm³ of liquid = y

From our Question above, our system of equations is given as:

x + y = 400........ Equation 1

x = 400 - y

1.2 × x + 1.8 × y = 1.6 × 400

1.2x + 1.8y = 640..... Equation 2

We substitute, 400 - y for x in Equation 2

1.2(400 - y) + 1.8y = 640

480 - 1.2y + 1.8y = 640

- 1.2y + 1.8y = 640 - 480

0.6y = 160

y = 160/0.6y

y = 266.67 g

Solving for x

x = 400 - y

x = 400 - 266.67g

x = 133.33g

Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g

7 0
2 years ago
The burger details:
sveticcg [70]
Set up proportion  170/180=x/1  than cross multiply  170x=180 divide both sides by 170   answer 0.944  so 94% remains
6 0
2 years ago
A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If
inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

(5+x)(10+x)=84

solve for x

Apply distributive property

50+ 5x+10x+x^2=84\\x^2+15x-34=0

solve the quadratic c equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+15x-34=0  

so

a=1\\b=15\\c=-34

substitute in the formula

x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}

x=\frac{-15\pm\sqrt{361}} {2}

x=\frac{-15\pm19} {2}

x=\frac{-15\pm19} {2}=2

x=\frac{-15\pm19} {2}=-17

therefore

The solution is x=2 ft

8 0
3 years ago
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