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2 years ago

Show work and Evaluate 3/4 + 2/5

Mathematics

1 answer:

frez [133]2 years ago

5 0

Answer:

23/20

Step-by-step explanation:

Find the common denominator of the 2 fractions (It's 20):

3/4 + 2/5

Multiply both numerator and denominator by 5 for the first fraction and multiply by 4 for the second fraction:

15/20 + 8/20

Add the fractions together:

23/20

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A video game displays 132 frames in 6 seconds on Penelope's computer. What is the rate in frames per second?

juin [17]

Answer:

$unit\ rate=22\ frames\ per\ second$

Step-by-step explanation:

we know that

To find the unit rate , divide the total frames by the total seconds

Let

x ----> the total frames displayed by the video game

y ----> the total seconds

$unit\ rate=\frac{x}{y}$

we have

$x=132\ frames\\y=6\ seconds$

substitute the values

$unit\ rate=\frac{132}{6}=22\ frames\ per\ second$

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3 years ago

686.924 to the nearest ten

xenn [34]

686.924 to the nearest ten is 690.0 because the ones place is a number of 5 and above, which means you must move the tens place up 1 value.

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2 years ago

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I need help is it A B C or D

babunello [35]

The answer is C. 680 is the initial value and 4.3 is the growth rate.

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2 years ago

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I think the answer is A Correct?

xeze [42]

You can see that there are 6 rock CDs, over a total of

$6+10+4+8+12 = 40$

So, the ratio of rock CDs over the total number of CDs is

$\dfrac{6}{40} = 0.15$

Which is 15%.

So, yes, the answer is A

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2 years ago

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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |subtract $y$ from both sides

$\dfrac{2}{3}x-y+b=0$ |multiply both sides by 3

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |multiply both sides by $\sqrt{13}$

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |divide both sides by 3

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

2 years ago