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2 years ago

Can I get a bit of help

Mathematics

1 answer:

Phantasy [73]2 years ago

5 0

she can count the number of row and the number of square in each row, or she can add 6 and 8

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the floor plan is 22' in length, and 12' in width. What is the ratio of the length of the room to it's area? where Area = Length

Alenkinab [10]

The ratio of the length of the room to its area is
$\frac{22}{12 \times 22} = \frac{1}{12}$

4 0

2 years ago

A recipe called for 2/9 cup of chopped tomatoes and 4/7 cup of diced tomatoes. In total how many cups of tomatoes did the recipe

kolbaska11 [484]

50/63

You add them

.....
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4 0

3 years ago

Read 2 more answers

I cant seem to get one of these answers when i work it out. please help

lisov135 [29]

Answer:

first option

Step-by-step explanation:

To obtain ( f ￮ g)(x) substitute x = g(x) into f(x) , that is

f( $\frac{1}{2x}$ )

= $\frac{2}{\frac{1}{2x}+3 }$ ( multiply numerator/ denominator by 2x to clear the fraction

= $\frac{2(2x)}{2x(\frac{1}{2x}+3) }$

= $\frac{4x}{1+6x}$

3 0

2 years ago

A rectangle has a a perimeter of 72 ft. The length and width are scaled by a factor 3.5.

jarptica [38.1K]

Formula for perimeter of rectangle:
P=2(L+w)
P=2L+2w
Here Perimeter, p= 72 ft
And scale factor of length and width=3.5 which means rectangle is enlarged.
So perimeter of rectangle= 3.5 x 72
P=252ft

Answer: 252 ft

8 0

3 years ago

Read 2 more answers

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago