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3 years ago

Need help please on Pre Calculus!!! Directions: verify each identity

Mathematics

1 answer:

Juliette [100K]3 years ago

3 0

You first simplify

tan(x) = cos(x)/sin(x) and cot(x) = sin(x)/cos(x)

Then you plug that in and then you simplify even more

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6 movie tickets cost $72. At this rate, how much would 2 movie tickets cost? Use any method or strategy to show how you solved t

Alina [70]

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Answer: 24$

Explanation:

72 / 6 = 12$

12$ for 1 ticket

12 x 2= 24$ for 2 tickets

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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5 0

3 years ago

What is the least number of colors you need to correct color in the sections of these pictures so that no two touching sections

Kobotan [32]

You would assume that in this figure, the number of colored sections with which are not colored with respect to a " touching " colored section, would be half of the total colored sections. However that is not the case, the sections are not alternating as they still meet at a common point. After all, it notes no two touching sections, not adjacent sections. Their is no equation to calculate this requirement with respect to the total number of sections.

Let's say that we take one triangle as the starting. This triangle will be the start of a chain of other triangles that have no two touching sections, specifically 7 triangles. If a square were to be this starting shape, there are 5 shapes that have no touching sections, 3 being a square, the other two triangles. This is presumably a lower value as a square occupies two times as much space, but it also depends on the positioning. Therefore, the least number of colored sections you can color in the sections meeting the given requirement, is 5 sections for this first figure.

Respectively the solution for this second figure is 5 sections as well.

7 0

3 years ago

A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s

RoseWind [281]

Answer:

There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).

The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

4 0

3 years ago

Suppose we want to choose colors, without replacement, from the colors red, blue, green, and purple.

DerKrebs [107]

The number of ways when the choice is not relevant is 4

<h3>How to determine the number of ways?</h3>

The number of colors are:

Colors, n = 4

The color to choose are:

r = 3

<u>Relevant choice</u>

When the choice is relevant, we have:

$Ways = ^nP_r$

This gives

$Ways = ^4P_3$

Evaluate

Ways = 24

Hence, the number of ways when the choice is relevant is 24

<u>Not relevant choice</u>

When the choice is not relevant, we have:

$Ways = ^nC_r$

This gives

$Ways = ^4C_3$

Evaluate

Ways = 4

Hence, the number of ways when the choice is not relevant is 4