Answer:
C
Step-by-step explanation:
<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
Answer:
x = 3 1/2
Step-by-step explanation:
You could simplify the given equation first, then solve the resulting 2-step linear equation. It might work better to undo the operations done to the variable.
<h3>Solution</h3>
(5 1/6 -x)(2.7) -5 3/4 = -1 1/4 . . . . . given
(5 1/6) -x)(2.7) = 4 1/2 . . . . . . . add 5 3/4 to both sides
(5 1/6 -x) = 4.5/2.7 = 5/3 . . . divide by 2.7
31/6 -10/6 = x . . . . . . . . . . add x-5/3, use common denominators
21/6 = x = 7/2
x = 3 1/2
4/20 is 0.20, which is equivalent to 20%.
Remember that 1.0=100%, 0.5=50%, 0.2=20%, 0.05=5%, and so on.
The answer is 6hours in 122 minutes do umknow
