Si 22 patos tienen comida para 10 dias, si tenemos 5 patos ¿cuantos días tendrían comida?
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Given:
Initial number of bacteria = 3000
With a growth constant (k) of 2.8 per hour.
To find:
The number of hours it will take to be 15,000 bacteria.
Solution:
Let P(t) be the number of bacteria after t number of hours.
The exponential growth model (continuously) is:
Where, is the initial value, k is the growth constant and t is the number of years.
Putting in the above formula, we get
Taking ln on both sides, we get
Therefore, the number of bacteria will be 15,000 after 0.575 hours.
