Answer:
The new car costs more
Old car = $5062.125
New car = $7161.357
Step-by-step explanation:
Manny drives an average of 110 miles per week with his old car. The old car gets 16 miles per gallon. The cost per gallon is $2.65 repair and Maintainance costs an average of $740 per year.
For the old car, to find the amount spent on the car we have
110/16 * 2.65 = $18.21875 / week
There are 52 weeks in a year. We have
10.21875*52 = $ 947.375
947.375 + 740
= $1687.375
= 1687.357 * 3
= $5062.125
The new car cost $6500 over a three year loan process.
The car gets 28 miles per gallon. It requires a maintenance f $10 per month. For the new car to find the amount, we have
110*28 * 2.65 *52 = $541.357
541.357 + 10(12) + 6500
= $7161.357
Answer:
Standard amperage sizes of the Code are 15, 20, 25, 30, 35, 40, 45, 50, 60, ... Additional standard ampere ratings for fuses are 1, 3, 6, 10 and 601
Step-by-step explanation:
Answer:
what are you asking for
Step-by-step explanation:
Answer:
x = 10.52 m
Step-by-step explanation:
Given that,
Length of a park = 90 m
Width of a park = 60 m
Area, A = 9000 m²
A uniform strip borders all four sides of the park for parking. We need to find the width of the strip. Let it is x. Now the area becomes,
(90+2x)(60+2x) = 9000

So, the width of the strip is equal to 10.52 m.