All categories

2 years ago

A rectangle has perimeter 56 cm and length 21 cm. What is its width?

Mathematics

2 answers:

Ymorist [56]2 years ago

5 0

Answer:

width=7 cm

Step-by-step explanation:

perimeter=2(lengths+width)

56 =2(21+x)

56 =42+2x

56-42 =2x

2x = 14

x =7

therefore the width=7 cm

Misha Larkins [42]2 years ago

4 0

<h3>answer the answer is 7. </h3>

hhhhhhhhhhh

You might be interested in

What is the input-output table for the function f(x) = 3x^2-x+4

mojhsa [17]

Answer:

Step-by-step explanation:

The input-output table can be made by putting value of x and finding the value of f(x)

f(x) = 3x^2-x+4

f(0) = 3(0)^2-0+4 = 0-0+4 = 4

f(1) = 3(1)^2-1+4 = 3-1+4 = 2+4 =6

f(2) = 3(2)^2-2+4 = 3(4)-2+4 = 12-2+4 = 10+4 = 14

f(3) = 3(3)^2-3+4 = 3(9)-3+4 = 27-3+4 = 24+4 = 28

So put value of x and find f(x) and fill the input-output table.

x f(x)

0 4

1 6

2 14

3 28

3 0

2 years ago

Jacob and Sarah are saving money to go on a trip. They need at least $2000 in order to go. Jacob mows lawns and Sarah walks dogs

Paladinen [302]

Answer:

$20x+10y\ge 2000$

Step-by-step explanation:

Let x represent the number of lawns Jacob mowed and y represent the number of dogs Sarah walked.

Jacob charges $20 each time he mows a lawn, then he earns $20x for x lawns mowed.

Sarah charges $10 each time she walks a dog, then she earns $10y for y dogs walked.

In total, they will earn $(20x + 10y). They need at least $2000 in order to go on a trip, then

$20x+10y\ge 2000$

Note that $x\ge 0,\ y\ge 0.$

7 0

3 years ago

A circle with circumference 20 has an arc with 72 degree central angle what is length of the arc

Debora [2.8K]

Answer:

Step-by-step explanation:

<em>Look at the picture.</em>

<em />

<em>At the beginning we have to calculate what part of the angle 360° is the given angle 75°.</em>

<em /> $\dfrac{75}{360}=75:360=0.2$ <em />

<em>The same part of the circumference of the circle is the arc defined by this central angle.</em>

The circumference <em>C = 20</em>.

Therefore

$x=0.2\cdot20=4$

4 0

2 years ago

Jessie estimates the weight of her cat to be 10 pounds. The actual weight of the cat is 13.75 pounds. find the percent error.

romanna [79]

Answer:

$\large \boxed{27 \, \%} }$

Step-by-step explanation:

$\begin{array}{rcl}\text{Percent error}&= &\dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \,\%\\\\& = & \dfrac{\lvert 10 - 13.75\lvert}{13.75} \times 100 \, \% \\\\& = & \dfrac{\lvert -3.75\lvert}{13.75} \times 100 \, \%\\ \\& = & \dfrac{3.75}{13.75} \times 100 \,\%\\\\& = & 0.27 \times 100 \, \%\\& = & \mathbf{27 \, \%}\\\end{array}\\\text{The percent error is $\large \boxed{\mathbf{27 \, \%} }$}$

3 0

2 years ago

How can Doug use place value pattern to check his answer?

MAVERICK [17]

He can use it to make sure he lined his place values up properly

3 0

2 years ago