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Zolol [24]
3 years ago
6

Help!!!!!!!!! Please!!!!

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

your answer is letter A,

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Show how to make a ten to solve 13-7
lara [203]
13-7=?

13-7 = 6

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4. Ayla purchased two pairs of jeans for $30.50 and a shirt for $20.75. She paid with a one hundred dollar bill
vodomira [7]
She will receive $48.75 back.
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PLEASE ASNWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!
lukranit [14]

Answer:

not sure but I feel like 6 because 3x2 is 6

3 0
3 years ago
Answer this question thanks:)
Viefleur [7K]

First multiply 2 to both sides to isolate q. Since 2 is being divided by q, multiplication (the opposite of division) will cancel 2 out (in this case it will make 2 one) from the left side and bring it over to the right side.

\frac{q}{2} × 2 < 2 × 2

q < 4

For the graph will you have a empty or colored in circle?

If the symbol is ≥ or ≤ then the circle will be colored in. This represents that the number the circle is on is included.

If the symbol is > or < then the circle will be empty. This represents that the number the circle is on is NOT included.

Which direction will the ray go?

If the variable is LESS then the number then the arrow will go to the left of the circle.

If the variable is MORE then the number then the arrow will go to the right of the circle.

In this case your inequality is:

q < 4

aka q is less then four

This means that the graph will have an empty circle and the arrow will go to the left of 4. (look at image below)

Hope this helped!

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8 0
3 years ago
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Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.
Umnica [9.8K]

The statements and their individual answers are not provided in the question. However, please check the explanation given below for the equation.

Step-by-step explanation:

  • The equation given is \frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 }
  • Divide the leading term of the dividend by the leading term of the divisor: \frac{2x^{4} }{2x^{2} }  = x^{2}
  •  Multiply it by the divisor: x^{2} ({2x^{2} -3x +1) = 2x^{4} - 3x^{3} + x^{2}
  • Subtract the dividend from the obtained result: (2x^{4} + 7x^{3} + 18x^{2} + 11x - 2) - (2x^{4} - 3x^{3} + x^{2} ) = (10x^{3} + 17x^{2} + 11x -2)
  • Divide the leading term of the obtained remainder by the leading term of the divisor: \frac{10x^{3}}{2x^{2} }  = 5x
  • Multiply it by the divisor: 5x (2x^{2} - 3x + 1) = 10x^{3} - 15x^{2} + 5x
  • Subtract the remainder from the obtained result: (10x^{3} + 17x^{2} + 11x -2) - (10x^{3} - 15x^{2} + 5x) = (32x^{2} + 6x - 2)
  • Divide the leading term of the obtained remainder by the leading term of the divisor: \frac{32x^{2} }{2x^{2} } = 16
  • Multiply it by the divisor: 16 (2x^{2} - 3x +1) = 32x^{2} - 48x +16
  • Subtract the remainder from the obtained result: (32x^{2} + 6x - 2) - (32x^{2} - 48x +16) = 54x - 18
  • Since the degree of the remainder is less than the degree of the divisor, then we are done.
  • Therefore,  \frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 } = (x^{2} + 5x +16 + \frac{54x - 18}{2x^{2}  - 3x +1})
7 0
3 years ago
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