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3 years ago

Which equation is represented by the graph below? pls asap

Mathematics

1 answer:

enot [183]3 years ago

5 0

Answer:

opt. 2

Step-by-step explanation:

take (4,0) as solution

0= -1/2(4)+2

= -2+2 = 0

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Solving Exponential and Logarithmic Equations In Exercise, solve for x. In x = 3

mixer [17]

Answer:

The solution is:

$x = e^{3} = 20.09$

Step-by-step explanation:

The first step to solve this equation is placing everything with the logarithmicto one side of the equality, and everything without the exponential to the other side. So

$\ln{x} = 3$

It already is in the desired format.

Now, we have that, since e and ln are inverse operations

$e^{\ln{a}} = a$

So, we apply the exponential to both sides of the equality

$e^{\ln{x}} = e^{3}$

$x = e^{3} = 20.09$

7 0

3 years ago

Lisa comprou um carro seminovo e, após ter um desconto de 6%, pagou R$ 2

emmasim [6.3K]

B.) R$ 27.160,00 would be the answer

4 0

3 years ago

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The Baker formula estimates the maximum heart rate, in beats per minute, of a person who is

seropon [69]

Answer:

For a=16, the Maximum Heart Rate is 188 Beats Per Minute.

Step-by-step explanation:

To begin, we know that the formula:

$b(a)=200-0.75a$ Eqn(1).

is equivalent to a linear equation of algebraic form denoted as:

$y=k+mx$ Eqn(2)

as such that Eqns (1) and (2) relate as follow:

$y$ ⇔ $b(a)$ : denoting our Dependent Variable, in this case Max. Heart Rate in Beats Per Minute

$x$ ⇔ $a$ : is our Independent Variable, in this case the Age of the Person

$m$ ⇔ $0.75$ : denoting the Rate of Change of the Age.

$k$ ⇔ $200$ : denoting our Constant.

Now in the question our value of $b(a)$ is given as 188 beats per minute, which by plugging in Eqn(1) gives:

$200-0.75a=188$

from which we can solve to obtain the value of $a$ as follow:

$-0.75a=188-200$ Gather similar terms on each side

$-0.75a=-12\\$ Simplify

$a=\frac{-12}{-0.75}$ Solve for $a$

$a=16$

Which tells us that at the Age of 16, the Max. Heart Rate is 188 Beats Per Minute.

4 0

3 years ago

Find the orthogonal complement W⊥ of W and give a basis for W⊥. W = x y z : x = 1 2 t, y = − 1 2 t, z = 6t.

igor_vitrenko [27]

Answer:

W⊥= (a, b, c)

a = v - (1/2)w

b = v

c = w

Basis for W⊥ = <(1,1,0),(-1/2,0,1)>

Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

(x,y,z)·(a,b,c) = 0

ax + by + cz = 0

So, taking into account that x=12t, y=-12t and z=6t, the equation above is equal to:

12ta + -12tb + 6tc = 0

12a - 12b + 6c = 0

Then, if we made b=v and c=w and solve for a, we get:

12a - 12v + 6w = 0

a = (12v - 6w)/12

a = v - (1/2)w

Therefore, the orthogonal complement W⊥ of W has the form:

W⊥ = (a,b,c) = (v - (1/2)w, v, w)

On the other hand, we can write W⊥ as:

W⊥ = (v - (1/2)w, v, w)

W⊥ = (v,v,0) + ((-1/2)w,0,w)

W⊥ = v(1,1,0) + w(-1/2,0,1)

That means that we can write any vector of W⊥ as a linear combinations of the vectors (1,1,0) and (-1/2,0,1), so they are a basis for W⊥

7 0

3 years ago

Evaluate -2/9-(-7/6)

kkurt [141]

Answer:

17/18

Step-by-step explanation:

- 2

–

- 7

-2 × 2

9 × 2

–

-7 × 3

6 × 3

-4

–

-21

-4 – -21

8 0

3 years ago

Read 2 more answers