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german
3 years ago
11

(13 less than a) How would this be solved in algebraic expression

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0

Answer:

<em>a </em>- 13

Step-by-step explanation:

a- 13 because you are taking 13 away from a

Vikentia [17]3 years ago
4 0

Answer: x-13 (?)

Step-by-step explanation:

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At the gift shop they sell small grettong card and large greeting cards. The cost of small ones are 1.80 and the cost of large o
Degger [83]

Answer:

$9

Step-by-step explanation:

Since the question only asks for small ones, we only need to focus on 1.80 and 5. Multiple them. 1.80×5 and we get 9. 1.80×5=9

6 0
3 years ago
A small country emits 120,000 kilotons of carbon dioxide per year. In a recent global
Svetradugi [14.3K]

The total carbon dioxide that the country would emit over the course of the 6 year period is 661,505 kilotons.

<h3>What is the total carbon dioxide that would be emitted?</h3>

The formula that can be used to determine the emission each year is:

Emission in the first year x(1 - rate of decrease)^number of years

Emission in the first year = 120,000

Emission in the second year = 120,000 x (1 - 0.034)^1 = 115,920

Emission in the third year = 120,000 x (1 - 0.034)^2 = 111,978.72

Emission in the fourth year = 120,000 x (1 - 0.034)^3 = 108,171.44

Emission in the fifth year = 120,000 x (1 - 0.034)^4 = 104,493.61

Emission in the sixth year = 120,000 x (1 - 0.034)^5 = 100,940.83

Sum of emissions from the first year to the sixth year = 661,505

This illustrates the concept of exponential decrease.

Learn more about exponential decrease on: brainly.com/question/24098168

#SPJ1

4 0
1 year ago
Solve for l, 2l+8=36
inna [77]

Step-by-step explanation:

2I+8=36

2I=36-8

2I=28

I=28/2

I=14

4 0
3 years ago
Convert the equation r = 12 sin theta to Cartesian coordinates. Describe the resulting curve.
VLD [36.1K]

Answer:

Step-by-step explanation:

Given that there is a polar equation as

r=12 sin \theta

This has to be converted into cartesian.

We know the conversion is

r^2 =x^2+y^2 \\tan \theta = \frac{y}{x}

Using this we can say that

sin^2 \theta = 1-cos^2 \theta \\= 1-\frac{1}{sec^2 \theta} \\=1-\frac{1}{1+tan^2 \theta} \\=1-\frac{1}{1+\frac{y^2}{x^2} } \\=1-\frac{x^2}{x^2+y^2} \\=\frac{y^2}{y^2+y^2}

\sqrt{x^2+y^2} =12(\frac{y}{\sqrt{x^2+y^2} } \\x^2+y^2 =12y\\x^2+y^2-12y+36 = 36\\x^2+(y-6)^2 = 6^2}

Circle with centre (0,6) and radius 6.

7 0
3 years ago
HELLPP PWEASEEEE :( im confused
Montano1993 [528]

Answer:

18 seconds

Step-by-step explanation:

according to the question

-16t²+5184=0 (0 because when the height is 0 the ball will hit the ground)

-16t²=-5184

t²=-5184/-16

t²=324

t=√324

t=18

8 0
3 years ago
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