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3 years ago

PLEASE HELP ASAP! BRAINLIEST! Find the missing variables of the triangles!

Mathematics

1 answer:

Luda [366]3 years ago

5 0

A is 28 good luck
Yeee

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Franny took a road trip to her grandmother’s house. She drove at a constant speed of 60 miles per hour for 2 hours. She took a b

bogdanovich [222]

Answer:

220 miles.

Step-by-step explanation:

Distance travelled = speed * time

Total distance travelled = 60 * 2 + 50*2

= 120 + 100

= 220 miles.

4 0

4 years ago

Read 2 more answers

2 liters of orange juice and 1.5 liters of applejuice

swat32

I assume you want the total of liters? 2 plus 1.5 equals 3.5 liters of juice all together :)

7 0

4 years ago

Find the total amount $20,700 at 9% compounded semiannually for 4 years

Phantasy [73]

Answer:

41,246.046 which could be rounded to .05 cents at the end.

Step-by-step explanation:

$20700(1.09)^8$

we use this equation since we are working with interest, and we are compounding interest twice per year, for 4 years or 8 times.

hope this helps, please rate and mark as brainelst.

4 0

2 years ago

Choose the true statement. -8 < 8 -8>8 -8=8

Aloiza [94]

Answer:

-8 < 8

Step-by-step explanation:

(-8) is smaller than 8...because for a value to be bigger...it has to be ahead of the other value(that its being compared to)...going in the positive direction of the numberline

8 0

4 years ago

Read 2 more answers

Suppose that 60 batteries are shipped to an auto parts store, and that 5 of those are defective. A fleet manager then buys 6 of

PIT_PIT [208]

Answer:

In 8910 ways can at least 4 defective batteries be included in the purchase

Step-by-step explanation:

The order in which the batteries are there is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

4 defective:

4 defective from a set of 5 and 2 non-defective from a set of 60 - 5 = 55. So

$C_{5,4}C_{60,2} = \frac{5!}{1!4!} \times \frac{60!}{2!58!} = 8850$

5 defective:

5 defective from a set of 5 and 1 non-defective from a set of 60 - 5 = 55. So

$C_{5,5}C_{60,5} = \frac{5!}{0!5!} \times \frac{60!}{1!59!} = 60$

In how many ways can at least 4 defective batteries be included in the purchase?

$T = 8850 + 60 = 8910$

In 8910 ways can at least 4 defective batteries be included in the purchase

8 0

3 years ago