9514 1404 393
Answer:
- Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
- Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E
Step-by-step explanation:
The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.
The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.
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<em>Additional comment</em>
The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.
Answer: It would be y=2x.
Answer is A.Rational number
Answer:
Find the complete table in attached file.
Step-by-step explanation:
Find the Incomplete table in attached file
Given:
A car travels 55 miles per hour for 2 hours.
So the speed of the car 55 miles per hour is constant for 2 hours.
Using speed formula.
Second row.
From the second row of the table 
and speed is constant 
, so we need to find only distance.
Third row.
From the third row of the table 
and speed is constant , so we need to find only distance.
Fourth row.
From the fourth row of the table 
and speed is constant , so we need to find time.
Therefore we complete the table from the above calculation.
The distance between the Earth's surface and the upper edge of the Earth's atmosphere would be Q - V.
The distance from the Sun to the Earth is Q. The distance from the Sun to the upper edge of the atmosphere is V. If you subtract V from Q, the remaining distance is that of the Earth's atmosphere. Q - V = the atmosphere
