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erica [24]
3 years ago
8

I need help from big brain

Mathematics
2 answers:
Irina-Kira [14]3 years ago
8 0
4 times because they have the same denominator and 8 divided by 2 is 4
marin [14]3 years ago
6 0

Answer:

\frac{8}{3} ÷ \frac{2}{3}

Step-by-step explanation:

If you are asking how many times does 8/3 goes into 2/3 then this means 8/3 is the dividend. The dividend is the number that is being divided by another number. This means the answer would be 8/3 divided by 2/3. I hope this makes sense.

I hope this helps :). If you have any questions let me know. Have a good day.

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umka2103 [35]

Answer: SA=33ft^2

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3 years ago
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How many times longer is the diameter of a grain of sand than the diameter of the average cell in the human body? Show your work
oee [108]
<span>A grain of sand has a diameter of slightly over 1 mm and the average diameter of a human cell is 8 micrometers. Putting them into common terms (meters) gives: 1.03 * 10^-3 m and 8*10^-6 m, respectively. Dividing the two to give a ratio leads to a value of (1.03*10^-3)/(8*10^-6), or 128.75 times longer for the grain of sand.</span>
5 0
3 years ago
Need help please, thank you
faust18 [17]
M<ABX + m<CBX = 180

therefore, (14x + 70) + (20x + 8) = 180

Subtract 78 from both sides. Divide by 34.
x = 3

Plug in 3 for x.

m<ABX = 14(3) + 70 = 112
m<CBX =20(3) + 8 = 68
5 0
4 years ago
SOLVE USING THE QUADRATIC FORMULA <br><br> 1) y=3x^2-x-6<br><br> 2) y=-5x^2+7x+3
kondor19780726 [428]

1) x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}

2) x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}

Step-by-step explanation:

Solving the equations using quadratic formula.

1) y=3x^2-x-6

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a =3, b = -1 and c= -6

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-1)\pm\sqrt{(-1)^2-4(3)(-6)}}{2(3)}\\x=\frac{1\pm\sqrt{1+72}}{6}\\x=\frac{1\pm\sqrt{73}}{6}\\so, x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}

2) y=-5x^2+7x+3

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a =-5, b = 7 and c= 3

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(7)\pm\sqrt{(7)^2-4(-5)(3)}}{2(-5)}\\x=\frac{-7\pm\sqrt{49+60}}{-10}\\x=\frac{-7\pm\sqrt{109}}{-10}\\So, x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}

Keywords: Solving Using Quadratic Formula

Learn more about Solving Using Quadratic Formula at:

  • brainly.com/question/10666510
  • brainly.com/question/4460262
  • brainly.com/question/7361044

#learnwithBrainly

3 0
4 years ago
Anyone know this !??!?!
omeli [17]

Answer:

its a, 2 and 3 only

Step-by-step explanation:

3 0
3 years ago
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