Solve. 2 — x 6 = 9 What’s the answer?

which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x

pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case if the point $(2,80)$ satisfied the exponential function

case A $f(x)=4(x^{5})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=4(2^{5})=128$

$128\neq 80$

therefore

the exponential function $f(x)=4(x^{5})$ not passes through the point $(2,80)$

case B $f(x)=5(x^{4})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=5(2^{4})=80$

$80=80$

therefore

the exponential function $f(x)=5(x^{4})$ passes through the point $(2,80)$

case C $f(x)=4(5^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=4(5^{2})=100$

$100\neq 80$

therefore

the exponential function $f(x)=4(5^{x})$ not passes through the point $(2,80)$

case D $f(x)=5(4^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=5(4^{2})=80$

$80=80$

therefore

the exponential function $f(x)=5(4^{x})$ passes through the point $(2,80)$

therefore

the answer is

$f(x)=5(x^{4})$

$f(x)=5(4^{x})$

7 0

3 years ago

A sample size of n= 20 is a simple random sample selected from a normally distributed

Alina [70]

Answer: 2.093

Step-by-step explanation: just took it

7 0

2 years ago

How you does this you how to fine what equal one

miskamm [114]

7/16 + 3/8 + Blank = 1
7/16 + 6/16 + 3/16 = 1
convert 3/8 to 6/16 then add 7+6 which = 13
that would be 13/16 then figure out that 13+3 =16 so 13/16+3/16= 16/16 or 1

6 0

3 years ago

Please help me , I need help!!!

GaryK [48]

Answer:

An odd number times an even number is always even

e.g 2 × 3 = 6

4 × 5 = 20

adding 1 to an even number makes it odd

6 + 1 = 7

20 + 1 = 21

hope this helps...

6 0

3 years ago

Read 2 more answers

Describe the nature of the roots for the equation 49x2 - 28x + 4 = 0.

Hoochie [10]

Answer:

We conclude that 49x² - 28x + 4 = 0 has only one real root.

Thus, option B i.e. one real root is the correct option.

Step-by-step explanation:

Given the equation

49x² - 28x + 4 = 0

comparing with the quadratic equation ax² + bx + c = 0 for x, where a ≠ 0,

here

a = 49, b = -28, c = 4

Determining the discriminant b²-4ac

b²-4ac = (-28)² - 4(49)(4)

= 784 - 784

= 0

It is clear that the discriminant b²-4ac is equal to zero.

i.e.

b²-4ac = 0

We know that if the discriminant b²-4ac = 0, then the quadratic equation has one real root.

Therefore, we conclude that 49x² - 28x + 4 = 0 has only one real root.

Thus, option B i.e. one real root is the correct option.

6 0

3 years ago