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3 years ago

IN NEED OF HELP LIKE ASAP!

Mathematics

2 answers:

pogonyaev3 years ago

8 0

The answer is 2^-5
Hope it helps

Ulleksa [173]3 years ago

7 0

Answer:

Below

Step-by-step explanation:

2^-3 / 2^2 is equal to 1 / 2^5

Write the expression in exponential form

2^-5 = 2^-5

Set the exponents as equal

-5 = -5

So this is true

Hope this helps! Best of luck <3

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The function y = f (x) is graphed below. What is the average rate of change of the function f(x) on the interval - 1 ≤ x ≤ 3?

jonny [76]

Answer:

$\displaystyle -2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Average Rate of Change: $\displaystyle \frac{f(b) - f(a)}{b - a}$

Step-by-step explanation:

Step 1: Define

Interval -1 ≤ x ≤ 3

a = -1, b = 3

f(a) = f(-1) = 4

f(b) = f(3) = -4

Step 2: Find Average

Substitute in variables [ARC]: $\displaystyle \frac{f(3) - f(-1)}{3 + 1}$
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3 years ago

Explain how a number line can be used to find the difference for 34-28

Luba_88 [7]

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3 years ago

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If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
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\end{cases}$

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\\\\\\
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\\\\\\
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\\\\\\
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4 years ago

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3 years ago

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Natalija [7]

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