It’s 19. The absolute value of -7 is 7 and the absolute value of 4 is 4. 7 plus 3 times 4 is 19.
The total number of students is 45 + 48 +40 = 133 students
1/2 * 133 ------ 3/4 * 133
(66.5 ; 99.75)
So we can say that b<span>etween 65 and 100 students packed their lunch</span>
To answer this, set up a system of equations. What we know is that
5x + 2y = 100
And...
x+y=38
x represents the unknown number of 5 points questions
y represents the unknown number of 2 point questions
In my opinion the easiest way to solve this is to use substitution (that is when you find out the value of one variable, either x or y, and substitute that value as the variable).
So,
x+y=38
Subtract x from both sides
y=38-x
Now, plug (38-x) in as y in the other equation.
5x + 2(38-x) = 100
5x + 76-2x= 100
3x+76=100
3x=24
x=8
Now that you know that x=8, you can solve for y.
5x+2y=100
5(8)+2y=100
40+2y=100
2y=60
---- ------
2 2
y=30
X=8
Y=30
There are 8 five point questions on the test and 30 two point questions on the test
Answer:
a=3√700b210b
Step-by-step explanation: