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inna [77]
3 years ago
6

(1+√5)/(3+√5) Surs and need all working as I do not know how to do this at all

Mathematics
1 answer:
Ronch [10]3 years ago
3 0

= \frac{(1 +  \sqrt{5}) }{(3 +  \sqrt{5}) }  \\

=  \frac{(1 +  \sqrt{5}) }{(3 +  \sqrt{5} )}  \times  \frac{(3 -  \sqrt{5} )}{(3 -  \sqrt{5}) }  \\

=  \frac{1(3 -  \sqrt{5}) +  \sqrt{5} (3 -  \sqrt{5}  )}{ ({3})^{2} -  { (\sqrt{5} })^{2}  }   \:  \: [∵ {a}^{2} -  {b}^{2}  = (a + b)(a - b) ]\\

=  \frac{3 -  \sqrt{5}  + 3 \sqrt{5} - 5 }{9 - 5}  \\

=  \frac{ - 2  + 2 \sqrt{5} }{4}  \\

=  \frac{2( - 1 +  \sqrt{5} )}{4}  \\

=  \frac{ - 1 +  \sqrt{5} }{2}  \\

\large\mathfrak{{\pmb{\underline{\red{Mystique35 }}{\red{}}}}}

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