Did I get this right? If not could someone explain this to me?

Mathematics

2 answers:

andreev551 [17]3 years ago

7 0

That is correct and good job on writing out what a independent and dependant variable is.

emmasim [6.3K]3 years ago

4 0

Correct!
Your notes on the right side are correct, too.

<em>In</em>dependent -- <em>not </em>dependent on another variable
Dependent -- dependent on another variable

The height of the plant varies because/due to of the quality/quantity of fertilizer.
So, the height is changed by the fertilizer.

Thus: height is dependent and fertilizer amount is independent.

You might be interested in

Hey can you help me answer this question by giving me the answer?

Leto [7]

The value of f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Given a function f(x)=4-2x+6 $x^{2}$ .

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6 $a^{2}$ (By just putting x=a).

f(a+h)== $4-2(a+h)+6(a+h)^{2}$

=4-2a-2h+6( $a^{2} +h^{2} +2ah$ )

=4-2a-2h+6 $a^{2} +6h^{2} +12ah$

= $6a^{2} +6h^{2}-2a-2h+12ah$

[f(a+h)-f(a)]/h=[ $6a^{2} +6h^{2}-2a-2h+12ah$ -(4-2a+6 $a^{2}$ )]/h

= $(6a^{2} +6h^{2} -2a-2h+12ah)/h$

= $(6h^{2} -2h+12ah)/h$

=6h+12a-2.

Hence the value of function f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Learn more about function at brainly.com/question/10439235

#SPJ1

7 0

2 years ago

Is -2 a solution of 2x+8=2?

Katarina [22]

Answer:2x+8=2

2x=2-8

2x= -6 (devide both sides by 2 to get x)

2x/2 and -6/2

×=3

Step-by-step explanation: