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3 years ago

Did I get this right? If not could someone explain this to me?

Mathematics

2 answers:

andreev551 [17]3 years ago

7 0

That is correct and good job on writing out what a independent and dependant variable is.

emmasim [6.3K]3 years ago

4 0

Correct!
Your notes on the right side are correct, too.

Independent -- not dependent on another variable
Dependent -- dependent on another variable

The height of the plant varies because/due to of the quality/quantity of fertilizer.
So, the height is changed by the fertilizer.

Thus: height is dependent and fertilizer amount is independent.

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Helpp

Alborosie

17 that’s the answer I did this one before

7 0

2 years ago

Duane is making cookies. The recipe calls for two times as many cups of sugar as butter, two times as many cups of oats as sugar

Ronch [10]

Answer:

Step-by-step explanation:

Let b represent the number of cups of butter needed.

Let s represent the number of cups of sugar needed.

Let o represent the number of cups of oat needed.

Let f represent the number of cups of flour needed.

The recipe calls for two times as many cups of sugar as butter. It means that

s = 2b

Two times as many cups of oats as sugar. It means that

o = 2s

Two times as many cups of flour as oats. It means that

f = 2o

If Duane puts in one cup of butter, it means that b = 1

Therefore,

s = 2 × 1 = 2 cups

o = 2s = 2 × 2 = 4 cups

f = 2o = 2 × 4 = 8 cups

Therefore, he needs to add 8 cups of flour

7 0

3 years ago

Write the decimal in standard form. 11-16 giving out 5 stars and thanks if its right!

alina1380 [7]

Answer:

11. 67.103

12. 7.25

13. 210.36

14. 10.5

15. 2.348

16. 72.2

hope that helps

5 0

2 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

2 years ago

Need help with trig!

dedylja [7]

Answer:

1. A. $4.42$