Answer:
m=-4/3
Step-by-step explanation:
Rise/run
it goes up -4 units and over 3
-4/3
Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
e. 0.08
Step-by-step explanation:
In the question above, a certain quantity of goods was supplied while a specific quantity of goods was sold per week. In a given week, if the number of proportion sold is X, therefore:
f(x) = {Γ(4+2)/Γ(4)Γ(2) x^3 (1-x), 0≤x≤1 ; 0, elsewhere
and
P(X greater than 0.9) =
= 20*{(y^4/4)[1,0.9] - (y^5/5)[1,0.9]} = 20*{(0.25 - 0.164) - (0.20 - 0.118)} = 20*{0.086 - 0.0819} = 20*0.0041 = 0.082
Therefore the probability of the proportion sold is approximately 0.082
Answer:
4
Step-by-step explanation:1.trust me
2.it will be it
3.just do it
We know that:
Profit = Revenue - Cost
Let us say x number of candies are made per week.
Finding Cost per week:
Cost of making 1 bar = 0.15
Cost of making x bars = 0.15x
Fixed rate of making candies per week = 600
Total cost of making x candies per week = 600 + 0.15x
Now let us find Revenue:
Selling price of each bar = 1.50
Selling price of x bars = 1.50x
Now we have to find profit,
Profit = Revenue - Cost
In order to have profit Revenue - Cost >0
So plugging values of revenue and cost to get number of candies,




x>444.44
Rounding off
x>444
Answer: The company must sell greater than 444 candies in order to make profit.