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dezoksy [38]
3 years ago
7

Does anybody know what they’ll ask on module 5 algebra one dba for flvs I need is ASAP

Mathematics
2 answers:
Allisa [31]3 years ago
5 0

Answer:

jPOINTS

Step-by-step explanation:

patriot [66]3 years ago
3 0

Answer:jpoints

Step-by-step explanation:

You might be interested in
Molly purchased 7 apples for $3.96. while looking at her receipt, Molly divided three $3.96 by 7. why might Molly perform this c
enot [183]
So she could figure out the price of each apple was.
6 0
3 years ago
You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car
zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year  = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = \frac{amount(1+r)^t - 1}{r (1+r)^t}

put here t = 10 and r = \frac{4.04}{200}

so

present value = \frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}

present value = 18089.96

so

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

so

now we calculate value of buyout

that is express as

amount = principal × (1+r)^{t}

amount = 3427.04 × (1+\frac{4.04}{200})^{10}

amount = 4185.74

so value of buyout is $4185.74

7 0
4 years ago
The question is in the picture ​
Lera25 [3.4K]
USE SOCRACTIC IT WOULD REALLY HELP WITH THIS QUESTION
8 0
3 years ago
3. Which statements about the line that passes through (-2, 0) and (2, -4) are true?
diamong [38]

Answer:

B, C, and D.

Step-by-step explanation:

Let's go through each answer choice.

A: To find the slope of a line from two points, we use this formula: (y_2-y_1)/(x_2-x_1). Plugging in the values (-2,0) and (2, -4), we get:

  • (-4-0)/(2+2)
  • -4/4
  • -1

Because option A says the slope is 1, but we got -1, option A is false.

B: To find the y-intercept, we use this formula: b = y_1 - m * x_1

  • b = 0 -(-1) * (-2)
  • b = 1 * (-2)
  • b = -2  

Since we know the value of b is the y-intercept, we could write the y-intercept as (0,-2). Therefore, option B is true.

C: The equation of a line (in slope-intercept form) is y = mx + b, where y - y-coordinate, m = slope, x = x-coordinate, and b = y-intercept. Since we already solved for the y-intercept and slope, let's plug in those values:

  • y = mx +b
  • y = -x -2

As you can see, the equation we got here matches the one in option C, meaning it's true.

D: We know that a point is written like this: (x, y). If the x-coordinate is not zero but the y-coordinate is, then it's the x-intercept. Since the question says that (-2,0) is one of the points the line passes through, and option D says that the x-intercept is (-2,0), it's true.

8 0
3 years ago
Read 2 more answers
4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

∵ f(x)=\sqrt{x-3}

∵ g(x) = x² + 3

∴ f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x

∴ <u><em>f(g(x)) = x</em></u>

∴ The functions are inverses; f(g(x)) = x

* <em>Lets find the inverse of h(x)</em>

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ \frac{x + 1}{3}=y^{2}

- Take √ for both sides

∴ ± \sqrt{\frac{x+1}{3}}=y

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

4 0
3 years ago
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