This question revolves around the concept of domain (primarily) and range (secondarily). The domain of the square root function is [0, +infinity).
The domain of "three times the sqrt of a" shares that domain: [0, +infinity).
We were not asked to come up with the range, but if the range is wanted, it is
[0, +infinity).
Answer:
The only non-zero fixed point is: x = 9/A.
The Step-by-step explanation:
A fixed point of a function is a points that is mapped to itself by the function; g(x) = x. Therefore, in order to find the fixed point of the given function we need to solve the following equation:
g(x) = x
x(10 - Ax) = x
10x - Ax² = x
10x - x -Ax² = 0
9x - Ax² = 0
Ax² - 9x = 0
The solutions of this second order equation are:
x = 0 and x = 9/A.
Since we are only asked for the non-zero fixed points, the solution is: 9/A.
<h2>
Answer:</h2><h2>D. 4b + 6</h2><h2 /><h2>Hope this helps!!</h2>
Answer:
9) y = -3x - 4
10) y = -1/3x + 14/3
11) y = x - 1
12) y = -7/5x - 18/5
13) y = 3/5x + 9/5
14) y = -2x - 3
Step-by-step explanation:
For this explanation, let's use the last problem as the example. You would use the formula y=mx+b. The first thing you would need to find would be the slope, or m. So, you would find the slope and conclude the answer is -2. After that, you would solve for b and get the answer. Hope this helped!
To figure this out first make the 4 4/9 into a improper fraction making it 40/9 and then multiply 2/7 x 40/9 then make is a mixed fraction :) hope this helped.
