X^2+6x=68 I think but I’m not sure
The asymptotes are in the picture
The answer is: 5 .
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Explanation: The solution is: m <span>> 5 .
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GIven the answer choices, m would not EQUAL "5", since m is GREATER THAN 5; or, "m </span> > 5 ".
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All the other answer choices: 7; 9, and 11, are all greater than 5; so they all could be solutions. The question asked which would NOT be solution for the value of "m". The answer choice given, "5", would not be a solution.
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How do we get: " m > 5 " ??
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We solve for "m"; or simplify; as follows:
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Given: 12m − 8 <span>> 52 ; Let us simplify to solve for "m";
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→ Add "8" to both sides;
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→ 12m − 8 + 8 > 52 + 8 ;
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→ to get: 12m > 60 ; → Now, divide EACH side of the inequality by "12"; to isolate "m" on one side of the equation; and solve for "m" ;
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→ 12m / 12 <span>> 60 / 12 ;
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</span>→ m > 5 ;
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Answer:
y=-6/7x-3
Step-by-step explanation:
On a graph, I plotted (7,-9) and the used the slope given but it was very off. On the slope -6/7x one of the plots is (7,-6). From the two lines, just go down 3 times and you would reach your plot again. What I mean is, do -6- 3=-9 so the answer is '- 6/7x-3. I used demos graphing calculator & calculator to make sure that my answer was 100% correct. You can use it too if you don't wan to use graph paper.
Hope this helps and comment or send a private message if you need help.
Answer:
see below
Step-by-step explanation:
We presume the damping constant is the opposite of the multiplier of time in the exponential term. Then the equations are ...
(a) y = a·e^(-ct)·sin(ωt)
(b) y = a·e^(-ct)·cos(ωt)
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These are the standard equations for simple harmonic motion assuming there is no driving function.
a = initial amplitude*
c = damping constant**
ω = frequency of oscillation in radians per second
t = time in seconds
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* Of course, when y(0) = 0, the motion never actually reaches this amplitude because it is subject to decay before it can.
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** In electrical engineering, damping is often specified in terms of a time constant, the time it takes for amplitude to decay to 1/e (≈36.8%) of the original amplitude. If that time is represented by τ, then the exponential factor is e^(-t/τ).
