For this case we have the following expression:
^ 5sqrt4x ^ 2 ^ 5sqrt4x ^ 2
Rewriting the expression we have:
((4x ^ 2) ^ (1/5)) ((4x ^ 2) ^ (1/5))
For power properties we have:
(4x ^ 2) ^ (1/5 + 1/5)
(4x ^ 2) ^ (2/5)
Rewriting we have:
(16x ^ 4) ^ (1/5)
^ 5sqrt16x ^ 4
Answer:
^5sqrt16x^4
Answer:
Step-by-step explanation:
Corresponding scores before and after taking the course form matched pairs.
The data for the test are the differences between the scores before and after taking the course.
μd = scores before taking the course minus scores before taking the course.
a) For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
b) We would assume a significance level of 0.05. The P-value from the test is 0.65. The p value is high. It increases the possibility of accepting the null hypothesis.
Since alpha, 0.05 < than the p value, 0.65, then we would fail to reject the null hypothesis. Therefore, it does not provide enough evidence that scores after the course are greater than the scores before the course.
c) The mean difference for the sample scores is greater than or equal to zero
Answer:
y = -4x - 4
Step-by-step explanation:
Rise/Run
-8/2 = -4
Y-intercept:
-4
I don’t know the rest, but I think the 1st and 3rd ones are true! I hope this helps some, I’m sorry if it’s incorrect!
Answer:
x = 3 or x = 2 or x = -1 or x = -5
Step-by-step explanation:
Solve for x:
((x - 3) (x - 2) (x + 1) (x + 5))/x = 0
Multiply both sides by x:
(x - 3) (x - 2) (x + 1) (x + 5) = 0
Split into four equations:
x - 3 = 0 or x - 2 = 0 or x + 1 = 0 or x + 5 = 0
Add 3 to both sides:
x = 3 or x - 2 = 0 or x + 1 = 0 or x + 5 = 0
Add 2 to both sides:
x = 3 or x = 2 or x + 1 = 0 or x + 5 = 0
Subtract 1 from both sides:
x = 3 or x = 2 or x = -1 or x + 5 = 0
Subtract 5 from both sides:
Answer: x = 3 or x = 2 or x = -1 or x = -5
