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2 years ago

7

Is -15 an integer and rational number?

2 answers:

WARRIOR [948]2 years ago

7 0

Answer:

I guess it would help you

antiseptic1488 [7]2 years ago

4 0

I hope this helps i’m not to sure if it is a integer or a rational number

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What are the roots to<br> the equation<br> 2x² + 6x-1=0?

lys-0071 [83]

Answer:

The roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = $\frac{ - b}{a}$

And products of roots = $\frac{c}{a}$

So, m + n = $\frac{ - 6}{2}$ = - 3

And m × n = $\frac{ - 1}{2}$

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 ( $\frac{ - 1}{2}$ )

Or, (m - n)² = 9 + 2 = 11

I.e m - n = $\sqrt{11}$

Again m + n = - 3 And m - n = $\sqrt{11}$

Solving this two equation

(m + n) + ( m - n) = - 3 + $\sqrt{11}$

I.e 2 m = - 3 + $\sqrt{11}$

Or, m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$

Similarly n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Hence the roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$ Answer

6 0

3 years ago

Please help and explain I don’t get it

VMariaS [17]

The answer is d, when you divide 45 by 54 you get 0.833333333333.... the line above the 3 means that there is infinite number of threes

3 0

3 years ago

Read 2 more answers

What is the value of m in the equation?<br> 3(18+ 2) = 4m<br><br> A.15<br> B.14<br> C.6<br> D.60

Yuki888 [10]

The value of m is D.15

4 0

2 years ago

Read 2 more answers

NEED HELP ASAP !! WILL MARK BRAINLEAST<br> SHOW WORK TOO !!!

irinina [24]

Step-by-step explanation:

$(1 + \cos(x) )(1 - \cos(x) )$

$1 - \cos {}^{2} (x)$

$= \sin {}^{2} (x)$

b.

$\frac{1}{ \cot {}^{2} (x) } - \frac{1}{ \cos {}^{2} (x) }$

$\frac{1}{ \frac{ \cos {}^{2} (x) }{ \sin { }^{2} (x) } } - \frac{1}{ \cos {}^{2} (x) }$

$\frac{1}{ \cot {}^{2} (x) } - \frac{ \csc {}^{2} (x) {} }{ \cot {}^{2} (x) }$

$\frac{ - \cot {}^{2} (x) }{ \cot {}^{2} (x) }$

$- 1$

c.

$\sec {}^{2} ( \frac{\pi}{2} - x ) )( \sin {}^{2} (x) - \sin {}^{4} (x))$

$( \csc {}^{2} (x) )( \sin {}^{2} (x) - \sin {}^{4} (x )$

$\csc {}^{2} (x) ( \frac{1}{ \csc {}^{2} (x) } - \frac{1}{ \csc {}^{4} (x) } )$

$1 - \frac{1}{ \csc {}^{2} (x) }$

$1 - \sin {}^{2} (x)$

$\cos {}^{2} (x)$

3 0

2 years ago

Factor the expression (x+4)^2-4y^5(x+4)+4y^10

Kamila [148]

If you factor this,
it is (x+4-2y^5)^2

6 0

3 years ago