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Kryger [21]
3 years ago
12

How much time has passed from the first clock to the second clock?

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0
I believe 4 hours and 35 minutes has passed.

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Pls help me:) <br> A-(4•7)^-4<br> B-1/28^2<br> C-7^-2/4^2<br> D-(4•7)^4
Sergio039 [100]

Answer:

\frac{1}{(28)^{2} }

Step-by-step explanation:

Step 1;

Write expression

4^{-2} . 7^{-2\\\frac{\frac{1}{4^{-2} } }{y\frac{1}{7^{-2} } } }

\frac{1}{4^{2} .7^{2} }

\frac{1}{(4x7)^{2} }

\frac{1}{(28)^{2} }

8 0
3 years ago
1.4=0.7p solve the equation
WINSTONCH [101]
You need to isolate p:
1.4 divided by 0.7 = 0.7p divided by 0.7 (this eliminates 0.7)
2 = p
4 0
3 years ago
Read 2 more answers
Pls do this thankuso much​
sergiy2304 [10]

Ans: D

differentiate sinx=cosx and differentiate x=1

:)

8 0
2 years ago
In triangle ABC, the measure of angle B is 50 degrees. Select all possible values for the measures of A and C if ABC is an acute
galben [10]

Answer:

Step-by-step explanation:

Sum of angle in a triangle = 180°

<A+<B+<C = 180

Given <B = 50°

Substituting into the formula

<A+50+<C = 180

<A+<C = 180-50

<A+<C = 130°

Since the ∆ABC is an acute triangle, the angles <A and <C must be angles less than 90° since acute angles are angles less than 90°

The possible values of <A and <C that will be acute and give a sum of 130° are;

∠A= 58° and ∠C= 72°

∠A= 80° and ∠C= 50°

∠A= 60° and ∠C= 70°

You can see that all the Angles are less than 90° and their sum is 130°

5 0
3 years ago
PLEASE PLEASE PLEASE HELP
Cloud [144]
Your rise over run will be -3 over 1 your going to start at the point 5 on the y-axis when your at the point 5 go down 3 then over to the right 1 keep going till it off the graph. Now do the opposite way and go up 3 from 5 and to the left 1 and keep doing that till it’s off the graph.

Hope this helps
6 0
3 years ago
Read 2 more answers
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