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Crank
2 years ago
8

I need help urgent Please will give brainly

Mathematics
1 answer:
valkas [14]2 years ago
6 0

Answer:

The order you placed it in at first was correct.

Step-by-step explanation:

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Helllpppp!!!!!it is a log equation
Vaselesa [24]

I hope this is right

2log2log6(2)+3log6(t)+1/2xlog6(y)

6 0
2 years ago
(x,-4) and (2,8): m = -3 find the missing value. it is in slope formula.
Snezhnost [94]

Answer:

The value of x = 6

Step-by-step explanation:

Given

  • The point (x,-4)
  • The point (2,8)

To determine

  • m = -3

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

here:

  • (x₁, y₁) = (x, -4)
  • (x₂, y₂) = (2, 8)
  • m = -3

so substitute (x₁, y₁) = (x, -4) , (x₂, y₂) = (2, 8)  and m = -3

m =  [y₂ - y₁] /  [x₂ - x₁]

-3 =  [8 - (-4)] / [2 - x]

-3 = [12] / [2-x]  

-3 (2-x) = 12

-6+3x = 12

3x = 12+6

3x = 18

divide  both sides by 3

3x/3 = 18/3

x = 6

Therefore, the value of x = 6

7 0
3 years ago
If the first 4 terms of an infinite geometric sequence are 150, 120, 96, and 76.8, then the sum of all the terms in the sequence
hammer [34]

The sum of the sequence is 750

<h3>How to determine the sum of the series?</h3>

The series is given as:

150, 120, 96, and 76.8,

Start by calculating the common ratio using:

r = T2/T1

This gives

r = 120/150

r = 0.8

The sum of the series is then calculated as:

S = \frac{a}{1 - r}

This gives

S = \frac{150}{1 - 0.8}

Evaluate

S = 750

Hence, the sum of the sequence is 750

Read more about sequence at:

brainly.com/question/6561461

#SPJ1

4 0
1 year ago
Vehicle a averages 14 miles per gallon of gasoline, and vehicle b averages 36 miles per gallon of gasoline. at these rates, how
Dima020 [189]
72 or 28 is the answer i hope this helped you :)
3 0
3 years ago
Find the product of 2x2 + 3x - 6 and 4x3 - x + 7.​
yanalaym [24]

Answer:

8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42

Step-by-step explanation:

(2x^2 + 3x - 6)(4x^3 - x + 7)

8x^5 -2x^3 +14x^2 + 12x^4 - 3x^2 + 21x -24x^3 + 6x - 42

8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42

5 0
2 years ago
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