<h2>Length = 11</h2><h2>Width = 6</h2>
The area of a rectangle is 66 ft^2:
L * W = 66
Length of the rectangle is 7 feet less than three times the width:
L = 3W-7
Substitute L in terms of W:
(3W-7) * W = 66
Factorise the equation:
3W^2 -7W = 66
3W^2 - 7W - 66 = 0
Factors of 66 =
1 66, 2 33, 3 22, 6 11
(3W + 11) (W - 6) = 0
Solve for W:
3W + 11 = 0
3W = 11
W = 3/11
W - 6 = 0
W = 0 + 6
W = 6
Using the original equation, find L:
L = 3W-7
L = 3(6)-7
L = 18-7
L = 11
L * W = 66
11 * 6 = 66
Answer:
-16x-28
Step-by-step explanation:
Break it into little pieces; start with distributing the -7:
-7(5+x)
-35-7x
Now add the rest of the problem: 7-35-7x-9x
Combine like terms: 7-35 7x-9x
7-35=-28 7x-9x=-16x
Rearrange so the coefficient and variable are upfront, giving you:
-16x-28
4.
This is because 4 goes into 16 4 times, hence 4 x 4 being 16.
Therefore, the answer would be four.
Hope this helps!
That's pretty much a tricky question though
